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Igoryamba
3 years ago
11

When a candle burns what form of energy does the chemical energy in the candle change

Chemistry
1 answer:
soldier1979 [14.2K]3 years ago
8 0
The energy transforms from chemical energy to heat and light energy. Because when the candle burns a chemical reaction occurs, and produces heat and light.
You might be interested in
What is an endothermic reaction
musickatia [10]
Chemical reaction that absorbs heat from its environment
6 0
3 years ago
Read 2 more answers
Method A: Does not transfer heat through solids and requires a medium for heat transfer Method B: Requires a material medium and
Paha777 [63]

Method A is Convection

Method B is Conduction

Explanation:

From the problem, we can infer that method A is convection and method B is conduction.

Conduction, convection and radiation are the three main methods of heat transfer.

  • Conduction and convection requires material medium to propagate.
  • Radiation occurs in the absence of a material medium.
  • Conduction mostly occurs in solid. Here, heat is transferred from one hot end to the cold end of the solid. The vibration of the particles in the hot end causes the transfer of kinetic energy to the cold end until thermal equilibrium is reached.
  • In convection, heat is primarily transferred in fluids as a result of density differences. Convection involves the motion of the materials of the medium. Hot air is light and it rises whereas cold air is dense and it sinks.

Learn more:

Sun brainly.com/question/1140127

#learnwithBrainly

6 0
3 years ago
Assuming 100% dissociation, calculate the freezing point and boiling point of 1.22 m SnCl₄(aq). Constants may be found here.
Gekata [30.6K]

Answer:

T° freezing solution → -11.3°C

T° boiling solution → 103.1 °C

Explanation:

Assuming 100 % dissociation, we must find the i, Van't Hoff factor which means "the ions that are dissolved in solution"

This salt dissociates as this:

SnCl₄ (aq)  →   1Sn⁴⁺ (aq)  +   4Cl⁻  (aq)   (so i =5)

The formula for the colligative property of freezing point depression and boiling point elevation are:

ΔT = Kf . m . i

where ΔT = T° freezing pure solvent - T° freezing solution

ΔT = Kb . m . i

where ΔT = T° boiling solution - T° boiling pure solvent

Freezing point depression:

0° - T° freezing solution = 1.86°C/m . 1.22 m . 5

T° freezing solution = - (1.86°C/m . 1.22 m . 5) → -11.3°C

Boiling point elevation:

T° boiling solution - 100°C = 0.512 °C/m . 1.22 m . 5

T° boiling solution = (0.512 °C/m . 1.22 m . 5) + 100°C → 103.1 °C

8 0
3 years ago
Consider the following hypothetical aqueous reaction. A flask is charged with .065 mol of A in a total volume of 100.0 mL. The f
Inga [223]

Answer: 0.422 M⁻¹s⁻¹

Explanation: <u>Reaction</u> <u>Rate</u> is the speed of decomposition of the reactant(s) per unit of time.

A <u>Rate</u> <u>Law</u> relates concentration of reactants, rate reaction and rate constant:

r=k[A]^{x}[B]^{y}

where

[A] and [B] are reactants concentration

x and y are reaction order, not related to the stoichiometric coefficients

k is rate constant

r is rate

Before calculating rate constant, first we have to determine reaction order.

In this question, the reactio order is 2. So, the rate law for it is

-\frac{d[A]}{dt} =k[A]^{2}

and the integrated formula is

\frac{1}{[A]} =\frac{1}{[A]_{0}} +kt

in which

[A]₀ is initial concentration of reactant

Then, using initial concentration at initial time and final concentration at final time:

\frac{1}{0.031} =\frac{1}{0.065} +k(40)

40k=\frac{1}{0.031}-\frac{1}{0.065}

40k=32.26-15.38

k = 0.422

The rate constant for the reaction is 0.422 M⁻¹.s⁻¹

3 0
3 years ago
Hi how are u guys :)
xxTIMURxx [149]

Answer:

good just bored and you :)

7 0
3 years ago
Read 2 more answers
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