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Lady bird [3.3K]
2 years ago
7

Como se explica o fato de o diamante e o grafite serem formados pelo mesmo elemento, o carbono, e serem materiais completamente

diferentes?
Chemistry
1 answer:
Mkey [24]2 years ago
4 0

Answer:

Ver explicacion

Explanation:

La capacidad de un elemento de existir en diferentes formas en el mismo estado físico se conoce como alotropía.

No es solo el carbono el que exhibe alotropía. También se sabe que el azufre y el fósforo exhiben alotropía.

Hay dos alótropos cristalinos de azufre; grafito y diamante. El grafito y el diamante difieren en la disposición de los átomos de carbono y la naturaleza de los enlaces entre los átomos de carbono en ambas sustancias.

Por lo tanto, el grafito y el diamante tienen propiedades físicas y químicas observadas completamente diferentes debido a las diferencias en la disposición de los átomos de carbono en cada sustancia, así como a las diferencias en la naturaleza de los enlaces entre los átomos de carbono en ambas sustancias.

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For each of the following redox reactions in the, identify the oxidizing agent and the reducing agent.
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3 years ago
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ook at sample problem 18.12 in the 8th ed Silberberg book. Write a balanced chemical equation (salt hydrolysis). So acetate ion
vfiekz [6]

Answer:

Here's what I get  

Explanation:

1. Write the chemical equation

CH₃COO⁻ + H₂O ⇌ CH₃COOH + OH⁻; Kₐ = 2 × 10⁻⁵

Let's rewrite the equation as

A⁻ + H₂O ⇌ HA + OH⁻

2. Calculate Kb

K_{\text{b}} = \dfrac{K_{\text{w}}}{K_{\text{a}}} = \dfrac{1.00 \times 10^{-14}}{2 \times 10^{-5}} = 5 \times 10^{-10}

3. Set up an ICE table

                      A⁻ + H₂O ⇌ HA + OH⁻

I/mol·L⁻¹:      0.35                 0       0

C/mol·L⁻¹:       -x                  +x      +x

E/mol·L⁻¹:    0.35-x               x        x

4. Solve for x

\dfrac{\text{[HA ][OH$^{-}$]}}{\text{[A$^{-}$]}} = \dfrac{x^{2}}{0.35-x} = 5 \times 10^{-10}

Check for negligibility,

\dfrac{\text{[HA]}}{K_{\text{b}}} = \dfrac{0.35}{5 \times 10^{-10}} = 7 \times 10^{8}> 400\\\\\therefore x \ll 0.35\\\\\dfrac{x^{2}}{0.35} = 5 \times 10^{-10}\\\\x^{2} = 0.35 \times 5 \times 10^{-10} = 1.8\times 10^{-10}\\\\x = \sqrt{1.8\times 10^{-10}} = \mathbf{1 \times 10^{-5}}

5. Calculate the pOH

[OH⁻] = 1 × 10⁻⁵ mol·L⁻¹

pOH = -log[OH⁻] = -log(1 × 10⁻⁵) = 4.88

6. Calculate the pH.

pH + pOH = 14.00

pH + 4.88 = 14.00

pH = 9.12

Note: The answer differs from that given by Silberberg because you used only one significant figure for the Kₐ of acetic acid.

3 0
3 years ago
What is the "magic number' of valence electrons? How does this influence the type of bonds formed by various combinations of
svp [43]

Magic number is any number in electron shells that suggest stability. It corresponds to total number of electrons in filled electron shells.

If an electron is having magic number, then it forms stable bonds.

Explanation:

The magic numbers are 2,10,18,36,54, 86 and 126. This refers to the total number of electrons that an electron can have when it is completely filled.

Atomic nuclei which carries either of these nucleons have high binding energy as compared to others. Hence, they have high stability. Bonds in such elements are more strong.

Radioactive decay of such elements is very slow.

Eugene Winger coined the term "magic number".

6 0
3 years ago
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