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3 years ago

Hi how are u guys :)

Chemistry

2 answers:

xxTIMURxx [149]3 years ago

7 0

Answer:

good just bored and you :)

gtnhenbr [62]3 years ago

3 0

Answer:good

Explanation:

You might be interested in

Use the information for the isotopes of element X to calculate the average atomic mass of X, and identify the element. Isotope A

BigorU [14]

Answer

36.45 u; X = Cl

Explanation:

The atomic mass of X is the weighted average of the atomic masses of its isotopes.

We multiply the atomic mass of each isotope by a number representing its relative importance (i.e., its percent of the total).

Set up a table for easy calculation .

0.7577 × 34.969 u = 26.496 u

0.2423 × 36.965 u = 8.9566 u

TOTAL = 36.45 u

X = Cl

5 0

4 years ago

Read 2 more answers

What is the velocity of a first-order reaction when the reactant concentration is 6 x 10-2M and the rate constant is 8 x 103sec-

tresset_1 [31]

Answer:

D) 4.8 × 10² M/s

Explanation:

Let's consider the following generic reaction.

A → B

The rate law is:

v = k . [A]ⁿ

where,

v: velocity

k: rate constant

[A]: concentration of the reactant A

n: reaction order for A

What is the velocity of a first-order reaction when the reactant concentration is 6 × 10⁻²M and the rate constant is 8 × 10³s⁻¹?

v = k . [A]¹ = 8 x 10³s⁻¹ . 6 x 10⁻²M = 4.8 × 10² M/s

5 0

4 years ago

Chromium has an atomic mass of 51.9961 u and consists of four isotopes, 50 Cr , 52 Cr , 53 Cr , and 54 Cr . The 52 Cr isotope ha

Troyanec [42]

Answer : The atomic mass of $_{24}^{53}\textrm{Cr}$ isotope is 52.8367 amu

Explanation :

We know that:

Total percentage abundance of the isotope = 100 %

Percentage abundance of $_{24}^{50}\text{Cr}\text{ and }_{24}^{53}\textrm{Cr}\text{ isotopes}=[100-(83.79+2.37)]=13.84\%$

We are given:

Ratio of $_{24}^{50}\textrm{Cr}\text{ and }_{24}^{53}\textrm{Cr}$ isotopes = 0.4579 : 1

Percentage abundance of $_{24}^{50}\textrm{Cr}$ isotope = $\frac{0.4579}{(0.4579+1)}\times 13.84\%=4.37\%$

Percentage abundance of $_{24}^{53}\textrm{Cr}$ isotope = $\frac{1}{(0.4579+1)}\times 13.84\%=9.49\%$

Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.

Formula used to calculate average atomic mass follows: $\text{Average atomic mass }=\sum_{i=1}^n\text{(Atomic mass of an isotopes)}_i\times \text{(Fractional abundance})_i$ .....(1)

Let the mass of $_{24}^{53}\textrm{Cr}$ isotope be 'x'

For $_{24}^{50}\textrm{Cr}$ isotope:

Mass of $_{24}^{50}\textrm{Cr}$ isotope = 49.9460 amu

Percentage abundance of $_{24}^{50}\textrm{Cr}$ = 4.37 %

Fractional abundance of $_{24}^{50}\textrm{Cr}$ isotope = 0.0437

For $_{24}^{52}\textrm{Cr}$ isotope:

Mass of $_{24}^{52}\textrm{Cr}$ isotope = 51.9405 amu

Percentage abundance of $_{24}^{52}\textrm{Cr}$ isotope = 83.79 %

Fractional abundance of $_{24}^{52}\textrm{Cr}$ isotope = 0.8379

or $_{24}^{53}\textrm{Cr}$ isotope:

Mass of $_{24}^{53}\textrm{Cr}$ isotope = x amu

Percentage abundance of $_{24}^{53}\textrm{Cr}$ isotope = 9.49 %

Fractional abundance of $_{24}^{53}\textrm{Cr}$ isotope = 0.0949

For $_{24}^{54}\textrm{Cr}$ isotope:

Mass of $_{24}^{54}\textrm{Cr}$ isotope = 53.9389 amu

Percentage abundance of $_{24}^{54}\textrm{Cr}$ isotope = 2.37 %

Fractional abundance of $_{24}^{54}\textrm{Cr}$ isotope = 0.0237

Average atomic mass of chromium = 51.9961 amu

Putting values in equation 1, we get:

$51.9961=[(49.9460\times 0.0437)+(51.9405\times 0.8379)+(x\times 0.0949)+(53.9389\times 0.0237)]\\\\x=52.8367amu$

Hence, the atomic mass of $_{24}^{53}\textrm{Cr}$ isotope is 52.8367 amu

4 0

4 years ago

All forces require an input of ______ - mass - energy - speed - atoms

artcher [175]

Energy is the correct answer. I hope I helped you

5 0

3 years ago

The ________ is the energy difference between reactants and products in a chemical reaction. heat of reaction transition energy

bearhunter [10]

The answer is "heat of the reaction"

3 0

3 years ago