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ra1l [238]
3 years ago
5

Use the drop down to complete the following inequality.

Mathematics
2 answers:
andrew-mc [135]3 years ago
7 0

Answer:

The inequality is c+2< 1

Step-by-step explanation:

Tomtit [17]3 years ago
5 0

Answer:

The inequality is c+2< 1

Step-by-step explanation:

we know that

In the figure, the value of c is less than -1

so

c< -1

Adds both side +2

c+2< -1+2

c+2< 1

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Find the length of each line segment or object
meriva

Answer:

1 ⁷/₈ in

Step-by-step explanation:

that is exactly 1 ⁷/₈ in

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A disc has a diameter of 21 cm while a mini disc has a diameter of 14cm. Write the ratio of the mini disc diameter to the disc d
Serjik [45]

Answer:

mini disc diameter:disc diameter

14cm:21cm = 7:10.5 = 3.5:5.25 = 1:1.5

4 0
3 years ago
Which quiz did met have a better score?
MaRussiya [10]
I'm her first quiz she did better, this is going to be hard to explain but pay attention 92% as a decimal is 92/100 keep this in mind, then 27 out of 30 question we try to make 30 go into 100 but we know 30 can't go into 100 without a decimal so what we do is we change the decimal to 90 so for the 27 out of 30 it is now 81/90, now we need to change the denominator in 92/100 to 90 so we subtract 10 from the numerator and denominator to get 82/100 so compare the 2 decimals you got 81/90 and 82/90 and you find that 82/90 is bigger so she did better on the first quiz
7 0
3 years ago
Read 2 more answers
Rearrange the following and ad .005, 2,002.181, 795.41, 14.0,184
xz_007 [3.2K]

Answer:

1 2 3 4

Step-by-step explanation:

4 0
3 years ago
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g In R simulate a sample of size 20 from a normal distribution with mean µ = 50 and standard deviation σ = 6. Hint: Use rnorm(20
Illusion [34]

Answer:

> a<-rnorm(20,50,6)

> a

[1] 51.72213 53.09989 59.89221 32.44023 47.59386 33.59892 47.26718 55.61510 47.95505 48.19296 54.46905

[12] 45.78072 57.30045 57.91624 50.83297 52.61790 62.07713 53.75661 49.34651 53.01501

Then we can find the mean and the standard deviation with the following formulas:

> mean(a)

[1] 50.72451

> sqrt(var(a))

[1] 7.470221

Step-by-step explanation:

For this case first we need to create the sample of size 20 for the following distribution:

X\sim N(\mu = 50, \sigma =6)

And we can use the following code: rnorm(20,50,6) and we got this output:

> a<-rnorm(20,50,6)

> a

[1] 51.72213 53.09989 59.89221 32.44023 47.59386 33.59892 47.26718 55.61510 47.95505 48.19296 54.46905

[12] 45.78072 57.30045 57.91624 50.83297 52.61790 62.07713 53.75661 49.34651 53.01501

Then we can find the mean and the standard deviation with the following formulas:

> mean(a)

[1] 50.72451

> sqrt(var(a))

[1] 7.470221

5 0
3 years ago
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