Ask question

Ask question

All categories

Liono4ka [1.6K]

2 years ago

5

If 3y + 3 = y + 7 is the same as y + y +y + 1 + 1 + 1 = y + 1 + 1 + 1 + 1+ 1 + 1 + 1, then how can we isolate 'y' without disrup

ting the balance?

2 answers:

arsen [322]2 years ago

6 0

Answer 8x2 is 16

Step-by-step explanation:

Amanda [17]2 years ago

5 0

I don’t think he gave you the write answer but see if it’s Wrong let me know

You might be interested in

What value(s) of x make the following expression undefined? x^2+ 1

allsm [11]

Answer:x=2

Step-by-step explanation: 2x-4=0

2x-4=0

+4 +4

2x=4

2x/2=4/2

X=2

5 0

3 years ago

Write the equation of the line that passes through (5.-9) and (2.5).

Kipish [7]

Answer:

y = -14/3x + 43/3

Step-by-step explanation:

y2 - y1 / x2 - x1

5 - (-9) / 2 - 5

14 / -3

- 14/3

y = -14/3x + b

5 = -14/3(2) + b

5 = -28/3 + b

43/3 = b

y = -14/3x + 43/3

4 0

3 years ago

Does anyone know how to solve this

Fofino [41]

Here is the answer the app is called cymath btw

3 0

2 years ago

PLEASE HELP!!!!!!!!!!

yan [13]

$115 = l \times 2.5 \times 5.75$

$\huge \mathrm{Answer࿐}$

given :

$\longmapsto$ volume = 115 yd³

Dimensions are :

$2\frac{1}{2} yd$

$5\frac{3}{4} yd$

L

We know,

$\large \boxed{ \mathrm{volume = l \times b \times h}}$

$115 = 2\frac{1}{2} \times 5\frac{3}{4} \times l$

$l \times \dfrac{5}{2} \times \dfrac{23}{4} = 115$

$l \times \dfrac{115}{8} = 115$

$l = 115 \times \dfrac{8}{115}$

$l = 8 \: yd$

Therefore Length of the prism is 8 yards.

_____________________________

$\mathrm{ \#TeeNForeveR}$

5 0

2 years ago

f(x) = 3 cos(x) 0 ≤ x ≤ 3π/4 evaluate the Riemann sum with n = 6, taking the sample points to be left endpoints. (Round your ans

Kruka [31]

Answer:

$\int_{0}^{\frac{3 \pi}{4}}3 \cos{\left(x \right)}\ dx\approx 3.099558$

Step-by-step explanation:

We want to find the Riemann sum for $\int_{0}^{\frac{3 \pi}{4}}3 \cos{\left(x \right)}\ dx$ with n = 6, using left endpoints.

The Left Riemann Sum uses the left endpoints of a sub-interval:

$\int_{a}^{b}f(x)dx\approx\Delta{x}\left(f(x_0)+f(x_1)+2f(x_2)+...+f(x_{n-2})+f(x_{n-1})\right)$

where $\Delta{x}=\frac{b-a}{n}$ .

Step 1: Find $\Delta{x}$

We have that $a=0, b=\frac{3\pi }{4}, n=6$

Therefore, $\Delta{x}=\frac{\frac{3 \pi}{4}-0}{6}=\frac{\pi}{8}$

Step 2: Divide the interval $\left[0,\frac{3 \pi}{4}\right]$ into n = 6 sub-intervals of length $\Delta{x}=\frac{\pi}{8}$

$a=\left[0, \frac{\pi}{8}\right], \left[\frac{\pi}{8}, \frac{\pi}{4}\right], \left[\frac{\pi}{4}, \frac{3 \pi}{8}\right], \left[\frac{3 \pi}{8}, \frac{\pi}{2}\right], \left[\frac{\pi}{2}, \frac{5 \pi}{8}\right], \left[\frac{5 \pi}{8}, \frac{3 \pi}{4}\right]=b$

Step 3: Evaluate the function at the left endpoints

$f\left(x_{0}\right)=f(a)=f\left(0\right)=3=3$

$f\left(x_{1}\right)=f\left(\frac{\pi}{8}\right)=3 \sqrt{\frac{\sqrt{2}}{4} + \frac{1}{2}}=2.77163859753386$

$f\left(x_{2}\right)=f\left(\frac{\pi}{4}\right)=\frac{3 \sqrt{2}}{2}=2.12132034355964$

$f\left(x_{3}\right)=f\left(\frac{3 \pi}{8}\right)=3 \sqrt{\frac{1}{2} - \frac{\sqrt{2}}{4}}=1.14805029709527$

$f\left(x_{4}\right)=f\left(\frac{\pi}{2}\right)=0=0$

$f\left(x_{5}\right)=f\left(\frac{5 \pi}{8}\right)=- 3 \sqrt{\frac{1}{2} - \frac{\sqrt{2}}{4}}=-1.14805029709527$

Step 4: Apply the Left Riemann Sum formula

$\frac{\pi}{8}(3+2.77163859753386+2.12132034355964+1.14805029709527+0-1.14805029709527)=3.09955772805315$

$\int_{0}^{\frac{3 \pi}{4}}3 \cos{\left(x \right)}\ dx\approx 3.099558$

5 0

2 years ago