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Bumek [7]
4 years ago
5

Question:there are two 12 empty juice bottles. You drank 8 bottles of juice.i drank the rest. What fraction did I drank?

Mathematics
1 answer:
LenKa [72]4 years ago
8 0
Isn't it impossible to drink from an empty bottle?
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Solve for the variable <br> 10 + 25a = 75<br><br><br><br><br><br> Please help
Vesnalui [34]

Answer:

a = 2.6

Step-by-step explanation:

10 + 25a = 75

- 10.             - 10

25a = 65

÷25.     ÷25

a = 2.6

HOPE THIS HELPS

PLZZ MARK BRAINLIEST

8 0
3 years ago
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The perimeter of a square is 64 cm.<br> What is the length of the diagonal of the square?
Angelina_Jolie [31]
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3 years ago
You have two circles, one with radius r and the other with radius R. You wish for the difference in the areas of these two circl
gtnhenbr [62]

Answer:

maximum difference of radii =(r-R)=\frac{1}{2\pi ^{2}}

Step-by-step explanation:

We know that area of circle is given by

A=\pi \times (radius)^{2}

For circle with radius 'r' we have

A_{1}=\pi \times (r)^{2}

For circle with radius 'R' we have

A_{2}=\pi \times (R)^{2}

Now according to given condition we have

A_{1}-A_{2}\leq \frac{5}{\pi }

\Rightarrow \pi r^{2}-\pi R^{2}\leq \frac{5}{\pi }\\\\\Rightarrow (r^{2}-R^{2})\leq \frac{5}{\pi ^{2}}\\\\(r+R)(r-R)\leq \frac{5}{\pi ^{2}}\\\\\because (a^{2}-b^{2})=(a+b)(a-b)\\\\(r+R)=10(Given)\\\\\Rightarrow(r-R)\leq \frac{5}{10\pi ^{2}}\\\\\therefore (r-R)\leq\frac{1}{2\pi ^{2}}

Thus maximum difference of radii =(r-R)=\frac{1}{2\pi ^{2}}

6 0
4 years ago
Hansen is going on vacation and taking his dog Pickles along. Pickles eats 2 cups of Hungry Hound dog food each day. Hansen want
denis23 [38]

Answer:

he will go for 7 days

Step-by-step explanation:

because 1 day needs 2 coups and he need to take 14 coups it mean that he need 14÷2=7 he will go for 7 days

i think u get it thank u

5 0
2 years ago
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First we need to choose from "Posivite Test" column:
\frac{12}{12+78} =  \frac{12}{90} = 0,1333(3) 
3 0
4 years ago
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