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Slav-nsk [51]
3 years ago
13

What is the square root of 141?

Mathematics
2 answers:
Marrrta [24]3 years ago
7 0
The square root of 141
√141=11.87434208703792
serious [3.7K]3 years ago
6 0
The square root of 141 = \sqrt{141}

This is because the two factors are 3 and 47, which both aren't perfect squares. You cannot take anything out.

If you want it simplified (like with a calculator) it would be:
\sqrt{141} =11.87
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If one tosses a coin three times, write dow nthe possible observed number of heads and their probabilities
seropon [69]
You need to find the probability of Heads, Heads, Heads in 3 tosses;

P(HHH)= (1/2)(1/2)(1/2) <-- each toss has 2 possibilities and heads is one 
P(HHH)=1/8

Therefore, the probability of flipping 3 heads on a fair coin is 1/8 

Hope I helped :) 
6 0
3 years ago
Say a hacker has a list of n distinct password candidates, only one of which will successfully log her into a secure system. a.
alexdok [17]

Answer:

The probability is \frac{1}{n}

Step-by-step explanation:

If she has n distinct password candidates and only one of which will successfully log her into a secure system, the probability that her first first successful login will be on her k-th try is:

If k=1

P = \frac{1}{n}

Because, in her first try she has n possibles options and just one give her a successful login.

If k=2

P=\frac{n-1}{n} *\frac{1}{n-1} =\frac{1}{n}

Because, in her first try she has n possibles options and n-1 that are not correct, then, she has n-1 possibles options and 1 of that give her a successful login.

If k=3

P=\frac{n-1}{n} *\frac{n-2}{n-1} *\frac{1}{n-2} = \frac{1}{n}

Because, in her first try she has n possibles options and n-1 that are not correct, then, she has n-1 possibles options and n-2 that are not correct and after that, she has n-2 possibles options and 1 give her a successful login.

Finally, no matter what is the value of k, the probability that her first successful login will be (exactly) on her k-th try is 1/n

7 0
3 years ago
I don't understand raitos please help solve math problems
ollegr [7]
1st is to make the numbers into ratios. Basically taking the two numbers and putting them in the middle. I’ll do the 1st 15:36.
Next you put it into a fraction: 15/36
Put in the comments if you want me to do all or if you have any questions!
4 0
3 years ago
Can anyone help me on this please?
rjkz [21]
\dfrac{4a^3b^2+2a^2b^2+3ab}{ab}=\dfrac{4a^3b^2}{ab}+\dfrac{2a^2b^2}{ab}+\dfrac{3ab}{ab}=4a^2b+2ab+3
8 0
2 years ago
Can someone please help me out ?
gizmo_the_mogwai [7]

Answer:

205-160=<em>d</em>

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
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