600000 80000 10 expanded. form

Mathematics

1 answer:

kirza4 [7]3 years ago

7 0

600000+80000+10=680,010 six hundred eighty thousand ten

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Solving system of equations by substitution

weeeeeb [17]

Y=3x-10 and 3x+2y=16
y=3x-10
subsitute 3x-10 for y in other equation

3x+2y=16
3x+2(3x-10)=16
distribute
3x+6x-20=16
9x-20=16
add 20 both sides
9x=36
divide both sides by 9
x=4

sub back

y=3x-10
y=3(4)-10
y=12-10
y=2

x=4
y=2
(4,2) is soluiton

5 0

3 years ago

How do you find the answer so confused

alexandr402 [8]

For which question, I can help,
<span>for number 9, parallel lines have the same exact slope, so divide each of them by to isolate the y and then see if the slope (number multiplied by x) is the same as the other problems . PS: focus on the slope, rest of equation doesn't matter in this question</span>

5 0

3 years ago

Ax - b = c <br><br> Solve for x

7nadin3 [17]

ax - b = c

add b to each side

ax-b +b = c+b

ax = c+b

divide by a

ax/a = (c+b)/a

x = (c+b)/a

3 0

3 years ago

Read 2 more answers

Describe a real-world situation that can be modeled by the equation y = 1/20x. Be sure to describe what each variable represents

Mars2501 [29]

Ralph's height is y
Ben's height is x

Ben's height is 1/20 of Ralph's height. How tall is Ralph?

6 0

3 years ago

The cost to print digital photos at a local store is

snow_tiger [21]

<h2>The cost is same for both the options if we purchase 27 photos</h2>

Step-by-step explanation:

Cost of a photo at a local store is $0.25 per photo. This cost can be modeled to be linear in number of photos as $C_{1}(x)=0.25x$ .

Cost of photos purchased online is $0.15 per photo. However there is a shipping cost of $2.70. This can also be modeled to be linear in number of photos as $C_{2}(x)=2.70+0.15x$ .