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Cerrena [4.2K]
3 years ago
15

What is one way to test whether an unknown solution is acidic or basic?

Chemistry
2 answers:
ololo11 [35]3 years ago
8 0

<u>Answer:</u> The correct answer is Option B.

<u>Explanation:</u>

To determine the solution to be acidic or basic, one must use some indicators or by their properties.

Properties of acid:

  • It tastes sour.
  • It turns blue litmus paper to red.
  • It dissociates to give H^+ ions.
  • It does not feel soapy.

Properties of Bases:

  • It tastes bitter.
  • It turns red litmus paper to blue.
  • It dissociates to give OH^- ions.
  • It feels slippery just like soap.

Both of these solutions can conduct electricity. Hence, the correct answer is Option B.

jek_recluse [69]3 years ago
4 0

Answer: Option (B) is the correct answer.

Explanation:

Bases are the substances which contain OH ions within the molecule.

For example, solution of NaOH is a basic solution as it contains OH or hydroxide group.

Bases change red litmus into blue and bases have a slippery and soapy texture.

Therefore, we can conclude that out of the given options, one way to test whether an unknown solution is acidic or basic is to check whether the solution has a slippery feel.

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A. Gas atoms subjected to electricity emit bright lines of light

Explanation:

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The structure of two compounds are shown: which statement is true?
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Answer:

Explanation:

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8 0
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It’s about electron configuration
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3 0
3 years ago
A 7.300 gram sample of aluminum was quantitatively combined with a sample of selenium to form a compound. The compound weighed 3
adelina 88 [10]

Answer:

The empirical formula is Al2Se3  

Explanation:

<u>Step 1:</u> Data given

Mass of the sample of aluminium = 7.300 grams

Mass of the compound = 39.35 grams

Molar mass of aluminium = 26.98 g/mol

Molar mass of selenium = 78.96 g/mol

<u>Step 2:</u> Calculate mass of selenium

Mass of selenium = mass of compound - mass of aluminium

Mass of selenium = 39.35 - 7.3 = 32.05 grams

<u> Step 3:</u> Calculate moles of Al

Moles Al = Mass Al/ Molar mass Al

Moles Al = 7.300 grams / 26.98 g/mol

Moles Al = 0.2706 moles

<u>Step 4:</u> Calculate moles of Se

Moles Se = Mass Se / Molar mass Se

Moles Se =32.05 g / 78.96 g/mol

Moles Se = 0.4059 moles

<u>Step 5</u>: Divide through the smallest amount of mol

Aluminium: 0.2706 / 0.2706 = 1

Selenium: 0.4059/0.2706 = 1.5

This means for each mol aluminium, we have 1.5 moles of selenium

For each 2 moles of aluminium, we have 3 moles of selenium

The empirical formula is Al2Se3  

This is aluminium(III) selenide.

8 0
3 years ago
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