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3 years ago

It’s about electron configuration

Chemistry

1 answer:

Goryan [66]3 years ago

3 0

Answer:

True

Explanation:

A metal , has 1 electron on the last level, so it can become (A^+1)

C, non-metal, has 7 electrons on the last level, so it can become (C^-1)

Compound AC is possible

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The air we breathe contains different individual gases (mostly nitrogen and oxygen). Which of the following correctly describes

shusha [124]

Answer:

A. Mixture

Explanation:

Our air has a group of gases. For example, you said nitrogen & oxygen, Which is significantly a mixture.

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3 years ago

Draw a structure for a compound that meets the following description: An optically active compound, C5H10O with an IR absorption

Elenna [48]

Question: A optically active compound, C5H10O, exhibits IR absorption at 1730 cm-1.

Its carbon NMR shifts are given below. The number of hydrogen's at each carbon, determined by DEPT, is given in parentheses after the chemical shift.

13C NMR: δ 22.6 (3), 23.6 (1), 52.8 (2), 202.4 (1)

Draw the structure of this compound in the window below

Explanation:

3-methylbutanal is a butanal substituted by the methyl group at the 3rd position. It is a volatile constituent in the olive. Also, it is used as a flavoring agent and a plant metabolite, it is also a Saccharomyces cerevisiae metabolite. It is also called as the Isovaleraldehyde organic compound. The liquid is colorless at STP, and also found in very low concentrations. It is also seen to be produced commercially for different use. Mostly used compound reagent in the preparation of pharmaceuticals and pesticides.

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4 years ago

2.3 × 10^6 - 1.8 × 10^4

kykrilka [37]

2.282* $10^{6}$

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3 years ago

What is the molecular formula of ethene and water

nikklg [1K]

Explanation:

ethene C2H4

Water H2O

......

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2 years ago

Given the following information:

Katyanochek1 [597]

Step by Step Explanation

From the question,
the dimensions of the tank are;

L = 30 cm, way =0.075m and H = 15 cm

The density of water is given as
$D = 1g {cm}^{ - 3}$

The unit of density given in the question means that the mass of the water is in grams and the volume should also be in
${cm}^{3}$

To find the volume of the water, we first convert the units of dimensions given in inches and metres to centimetres

$1 inch = 2.54 cm$

This implies that ,

$H=15 inches=15×2.54cm=38.1cm$

Also,

$100cm=1m$

This implies that,
$w= \frac{0.075}{100 } = 7.5 \times {10}^{ - 4} cm$

Now, the volume of water in the tank can hold, can be found from the relation;

$V=L\times W\times H$

This implies that,

$v = 30cm \times (7.5 \times {10}^{ - 4} )cm \times 38.1cm$

$v = 0.857 {cm}^{3} \: to \: 3 \: d.p$

Finally, we can calculate the mass of the water from the relation given;

$D=\frac{M}{V}$

This in implies that

$1g {cm}^{ - 3} = \frac{m}{0.857 {cm}^{3} }$
$m = 1g {cm}^{ - 3} \times 0.857 {cm}^{3}$
$m = 0.857g$

Hence the fish tank can hold 0.857g water.

4 0

3 years ago

Read 2 more answers