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BARSIC [14]
3 years ago
11

Tính nộng độ mol/l của các chất tan trong các dung dịch sau: a) Trong 100ml dung dịch (A) có chứa 0,0365g HCl. (Cho: H=1; Cl=35,

5) b) Trong 50ml dung dịch H2SO4 có 0,0025mol
Chemistry
1 answer:
makkiz [27]3 years ago
8 0

Explanation:

2 Because visual specialization skills are important to success in so many career

fields, it is helpful to continue to build skill. What is one strategy you can use to

continue to improve your visualization skills?

Please someone help!!!

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What is the answer to number one
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2 the answer is 2 because 1.0 * 2 =2
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3 years ago
Q05 the "atomic number" of an atom is determined by the number of ________ it has.
Alexxx [7]
The atomic number of an atom is determined by the number of protons it has..

It is also the whole number shown on the periodic table 
6 0
4 years ago
Consider the following unbalanced redox reaction:
Olegator [25]
Mn04 is being reduced
5 0
3 years ago
Determine whether each molecule given below is polar or nonpolar. of2
sergejj [24]

Answer : The molecule OF_2 is a polar molecule.

Explanation :

Polar molecule : When the arrangement of the molecule is asymmetrical then the molecule is polar.

Non-polar molecule : When the arrangement of the molecule is symmetrical then the molecule is non-polar.

The given molecule is, OF_2

The electronegativities of oxygen and fluorine are different. The molecular geometry of OF_2 is bent. As, Fluorine is more elctronegative than the oxygen. So, the arrows putting towards the more electronegative element i.e, fluorine. These arrows do not balance each other. Due to this, the asymmetrical arrangement of these bonds makes the molecule polar.

Hence, the given molecule OF_2 is polar.

7 0
3 years ago
Consider the following reaction:
adell [148]

Answer:

1. d[H₂O₂]/dt = -6.6 × 10⁻³ mol·L⁻¹s⁻¹; d[H₂O]/dt = 6.6 × 10⁻³ mol·L⁻¹s⁻¹

2. 0.58 mol

Explanation:

1.Given ΔO₂/Δt…

    2H₂O₂     ⟶      2H₂O     +     O₂

-½d[H₂O₂]/dt = +½d[H₂O]/dt = d[O₂]/dt  

d[H₂O₂]/dt = -2d[O₂]/dt = -2 × 3.3 × 10⁻³ mol·L⁻¹s⁻¹ = -6.6 × 10⁻³mol·L⁻¹s⁻¹

 d[H₂O]/dt =  2d[O₂]/dt =  2 × 3.3 × 10⁻³ mol·L⁻¹s⁻¹ =  6.6 × 10⁻³mol·L⁻¹s⁻¹

2. Moles of O₂  

(a) Initial moles of H₂O₂

\text{Moles} = \text{1.5 L} \times \dfrac{\text{1.0 mol}}{\text{1 L}} = \text{1.5 mol }

(b) Final moles of H₂O₂

The concentration of H₂O₂ has dropped to 0.22 mol·L⁻¹.

\text{Moles} = \text{1.5 L} \times \dfrac{\text{0.22 mol}}{\text{1 L}} = \text{0.33 mol }

(c) Moles of H₂O₂ reacted

Moles reacted = 1.5 mol - 0.33 mol = 1.17 mol

(d) Moles of O₂ formed

\text{Moles of O}_{2} = \text{1.33 mol H$_{2}$O}_{2} \times \dfrac{\text{1 mol O}_{2}}{\text{2 mol H$_{2}$O}_{2}} = \textbf{0.58 mol O}_{2}\\\\\text{The amount of oxygen formed is $\large \boxed{\textbf{0.58 mol}}$}

8 0
4 years ago
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