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sdas [7]
3 years ago
15

An atom of fluorine has an atomic number of 9 and an atomic mass of 19. The atom contains

Chemistry
1 answer:
muminat3 years ago
8 0
The number of neutrons is the difference between the mass number and the number of protons. 

You get the element by looking at the atomic number which is the number of protons. In this case, it is 9 and yes, it is F. 

<span>However it is not an atom because it has 10 electrons so you have a fluoride ion F-. </span>

<span>The number of neutrons = 19 - 9 = 10

Therefore, the answer is D.

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
</span>
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A mutation can be defined as a change in an organism's
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Answer:

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2 years ago
Which planet would make the closest approach to Earth as the planet orbits the sun?
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D

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Match the following items. Match the items in the left column to the items in the right column. 1. general or nonspecific observ
ivann1987 [24]
when column B is like the attached pic: (missing in your question)

so the matches will be like that:

1- Qualitative :

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as Quantitative is a measured observation, It's an information or data based

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7 0
3 years ago
Which element would you expect to be more reactive: phosphorus (P) or fluorine (F)
Studentka2010 [4]

Answer:

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4 0
3 years ago
Read 2 more answers
Determine the empirical formula of a
k0ka [10]

Answer:

AuCl

Explanation:

Given parameters:

Mass of Gold  = 2.6444g

Mass of Chlorine  = 0.476g

Unknown:

Empirical formula  = ?

Solution:

Empirical formula is the simplest formula of a compound. Here is the way of determining this formula.

Elements                                     Au                                             Cl

Mass                                         2.6444                                     0.476

Molar mass                                 197                                          35.5

Number of moles                  2.6444/197                                 0.476/35.5

                                                 0.013                                           0.013

Divide by the

smallest                                 0.013/0.013                                 0.013/0.013

                                                       1                                                   1

The empirical formula of the compound is AuCl

3 0
3 years ago
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