To find the specification limit such that only 0.5% of the bulbs will not exceed this limit we proceed as follows; From the z-table, a z-score of -2.57 cuts off 0.005 in the left tail; given the formula for z-score (x-μ)/σ we shall have: (x-5000)/50=-2.57 solving for x we get: x-5000=-128.5 x=-128.5+5000 x=4871.50