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Lady_Fox [76]
3 years ago
8

A lightbulb has a normally distributed light output with mean 5000 end foot-candles and standard deviation of 50 end foot-candle

s. find a lower specification limit such that
Mathematics
1 answer:
Blizzard [7]3 years ago
8 0
To find the specification limit such that only 0.5% of the bulbs will not exceed this limit we proceed as follows;
From the z-table, a z-score of -2.57 cuts off 0.005 in the left tail; given the formula for z-score
(x-μ)/σ
we shall have:
(x-5000)/50=-2.57
solving for x we get:
x-5000=-128.5
x=-128.5+5000
x=4871.50
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Answer:

5/9=1/2

12/13=1

2/13=0

Step-by-step explanation:

These are just based on what I think and also

5/9=0.55... so closer to 0.5 which =1/2

12/13 is just really close to 13/13

2/13 is really close to 0/13 rather than 6.5/13, which is 1/2

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A ticket company charges a 4% service fee on all orders. How much is the service fee for a ticket that costs $65?
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Step-by-step explanation:

4 goes into 65    16 r1

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2 years ago
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Step-by-step explanation:

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3 years ago
A car la 160 inches long <br><br>A truck is 7percentage longer thanks they car​
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3 years ago
Please answer this with explanation. Please I really am struggling. I will mark you brainalist. Please solve it Please
Hatshy [7]

Answer:

13, 11, 4, 16, 6, 22

Step-by-step explanation:

<em>Let the second digit be x and the last digit be y</em>

Given:

  • Data set: 13, x, 4, 16, 6, y
  • Mean = 12
  • y = 2x or x = 2y

The mean of the data is the average. The average can be calculated by determining the sum of the terms and dividing it by the total digits.

\implies \text{Mean of data:} \ \dfrac{13 + x + 4 + 16 + 6 + y}{6} = 12

Let us substitute the value of y (2x) in the data.

\implies \dfrac{13 + x + 4 + 16 + 6 + 2x}{6} = 12

Now, add all the terms in the data and simplify.

\implies \dfrac{39 + x +2x}{6} = 12

\implies \dfrac{39 + 3x}{6} = 12

Distribute the denominators and simplify.

\implies \dfrac{39}{6} + \dfrac{3x}{6}  = 12

\implies  \dfrac{13}{2} + \dfrac{x}{2}  = 12

\implies  6.5 + \dfrac{x}{2}  = 12

Subtract 6.5 both sides and simplify.

\implies  6.5 + \dfrac{x}{2}  - 6.5 = 12 - 6.5

\implies \dfrac{x}{2} = 5.5

Use cross multiplication and simplify.

\implies x= 5.5 \times 2

\implies  x= 11

To determine the value of "y", simply substitute the value of "x" into the expression that represents the value of "y".

\implies y = 2x

\implies y = 2(11)

\implies y = 22

When the x and y values are substituted in the data, we get;

  • ⇒ 13, 11, 4, 16, 6, 22

Therefore, the data is 13, 11, 4, 16, 6, 22.

8 0
2 years ago
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