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To calculate the moles of AgNO3 in a solution, we need to know the volume and concentration of the solution.
Moles of AgNO3 = Volume of AgNO3 solution (L) * concentration of AgNO3 solution (M or mole/L) = 1.50 L * 0.050 M = 0.075 mole.
So 0.075 moles of AgNO3 are present in 1.50 L of a 0.050 M solution.
Answer:
protons only
Explanation:
proton is present in the nucleus of atom as sub atomic particle ..
proton has + charge in the it's top as p+..
Explanation:
The integrated rate law for the zeroth order reaction is:
![[A]=-kt+[A]_0](https://tex.z-dn.net/?f=%5BA%5D%3D-kt%2B%5BA%5D_0)
The integrated rate law for the first order reaction is:
![[A]=[A]_0e^{-kt}](https://tex.z-dn.net/?f=%5BA%5D%3D%5BA%5D_0e%5E%7B-kt%7D)
The integrated rate law for the second order reaction is:
![\frac{1}{[A]}=kt+\frac{1}{[A]_0}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B%5BA%5D%7D%3Dkt%2B%5Cfrac%7B1%7D%7B%5BA%5D_0%7D)
Where,
is the active concentration of A at time t
is the active initial concentration of A
t is the time
k is the rate constant