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anygoal [31]
3 years ago
9

WILL MARK AS BRAINLIEST Name the following ionic compounds.

Chemistry
1 answer:
STALIN [3.7K]3 years ago
7 0
1) Magnesium Chloride 
2) Sodium Bromide 
3) Magnesium Oxide
4) Nickel (III) Fluoride 
5) Aluminum Chloride
6) <span>Rubidium Sulfide
7) Gallium Nitride
8) Calcium Sulfide
9) </span><span>Lead (IV) Oxide
10) </span><span>Cobalt (II) Oxide
</span>11) B<span>eryllium Sulfide
12) </span><span>Cesium Nitride</span>
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17)<br> How many grams are in 0.02 moles of beryllium iodide, Bel2?
Alinara [238K]

Answer:

beryllium iodide has a molar mass of 262.821 g mol−1 , which means that 1 mole of beryllium iodide has a mass of 262.821 g . To find the mass of 0.02 moles of beryllium iodide, simply multiply the number of moles by the molar mass in conversion factor form.

Explanation:

5 0
3 years ago
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an apple pie needs 10 large apples, 2 crusts (top and bottom), one tablespoon of cinnamon. write a balanced equation that fits t
nasty-shy [4]
You're answer is 250 apples for 25 pies
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2 years ago
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Find the enthalpy of neutralization of HCl and NaOH. 137 cm3 of 2.6 mol dm-3 hydrochloric acid was neutralized by 137 cm3 of 2.6
liraira [26]

Answer : The correct option is, (D) 89.39 KJ/mole

Explanation :

First we have to calculate the moles of HCl and NaOH.

\text{Moles of HCl}=\text{Concentration of HCl}\times \text{Volume of solution}=2.6mole/L\times 0.137L=0.3562mole

\text{Moles of NaOH}=\text{Concentration of NaOH}\times \text{Volume of solution}=2.6mole/L\times 0.137L=0.3562mole

The balanced chemical reaction will be,

HCl+NaOH\rightarrow NaCl+H_2O

From the balanced reaction we conclude that,

As, 1 mole of HCl neutralizes by 1 mole of NaOH

So, 0.3562 mole of HCl neutralizes by 0.3562 mole of NaOH

Thus, the number of neutralized moles = 0.3562 mole

Now we have to calculate the mass of water.

As we know that the density of water is 1 g/ml. So, the mass of water will be:

The volume of water = 137ml+137ml=274ml

\text{Mass of water}=\text{Density of water}\times \text{Volume of water}=1g/ml\times 274ml=274g

Now we have to calculate the heat absorbed during the reaction.

q=m\times c\times (T_{final}-T_{initial})

where,

q = heat absorbed = ?

c = specific heat of water = 4.18J/g^oC

m = mass of water = 274 g

T_{final} = final temperature of water = 325.8 K

T_{initial} = initial temperature of metal = 298 K

Now put all the given values in the above formula, we get:

q=274g\times 4.18J/g^oC\times (325.8-298)K

q=31839.896J=31.84KJ

Thus, the heat released during the neutralization = -31.84 KJ

Now we have to calculate the enthalpy of neutralization.

\Delta H=\frac{q}{n}

where,

\Delta H = enthalpy of neutralization = ?

q = heat released = -31.84 KJ

n = number of moles used in neutralization = 0.3562 mole

\Delta H=\frac{-31.84KJ}{0.3562mole}=-89.39KJ/mole

The negative sign indicate the heat released during the reaction.

Therefore, the enthalpy of neutralization is, 89.39 KJ/mole

3 0
3 years ago
If the rock has a mass of 250.8 grams, what is its density?
cluponka [151]
To know the density you also need to know the volume of the rock.
4 0
3 years ago
Rubbing alcohol is less polar than water. Both are liquids at room temperature which One boils first? why?
Sergeeva-Olga [200]

Answer:

because both liquid are made from different substances.

Explanation:

8 0
3 years ago
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