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inysia [295]
3 years ago
11

The doctor ordered 750ml of a 15 percent solution. the stock solution is 50 percent. how much stock solution and diluent are nee

ded?
Chemistry
1 answer:
garik1379 [7]3 years ago
3 0
The doctor required a 15% 750mL solution. To lower the concentration of the solution, you have to add more diluting liquid. 

750mL * 0.15 = 112.5mL. This 112.5mL signifies the pure chemical or compound in the solution. This 112.5mL can be taken from the stock solution.

112.5 * 2 = 250mL of stock solution would be needed and 500 mL of the diluting agent should be added. Adding the two together would result to a 750mL solution of 15% concentration.  
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<u>Atomic Structure</u>

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<u>Step 3: Convert</u>

  1. [DA] Set up:                                                                                                       \displaystyle 993.6 \ g \ K_2SO_4(\frac{1 \ mol \ K_2SO_4}{174.27 \ g \ K_2SO_4})
  2. [DA] Divide [Cancel out units]:                                                                         \displaystyle 5.7015 \ mol \ K_2SO_4

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 4 sig figs.</em>

5.7015 mol K₂SO₄ ≈ 5.702 mol K₂SO₄

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