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3 years ago

A cheetah ran 300 feet in 2.92 seconds. What was the cheetah’s average speed in miles per hour? Show your work.

1 answer:

5 0

You would divide the cheetahs distance which is 300 feet by the cheetahs time which is 2.92 seconds
distance÷time
300÷2.92= 102.7 seconds or 103 seconds if you round up
the cheetahs speed is 102.7 seconds or 103 seconds

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4x + 6y - z=-18<br> 3x +2y - 4z = -24<br> - 5x + 3y + 2z = 15<br> find x y and z

Anna71 [15]

Answer:

x = -2, y = -1, z = 4

Step-by-step explanation:

4x + 6y - z=-18

z = 18 + 4 x + 6 y

3x +2y - 4z = -24

z = 6 + (3x)/ 4 + y /2

- 5x + 3y + 2z = 15

z = 15/2 + (5x)/2 - (3y)/2

18 + 4 x + 6 y = 6 + (3x)/ 4 + y /2 = 15/2 + (5x)/2 - (3y)/2

x = -22y/13 - 48/13

4(-22y/13 - 48/13) + 6y - (15/2 + (5(-22y/13 - 48/13))/2 - (3y)/2) = -18

Compute the output value of the variables x and y with respect to the input values of x, y, and z coefficients.

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3 years ago

Is the following statment true or false? explain your reasoning <br> 15+ (4x6) = (15+4) x6

Levart [38]

Answer:foot

Step-by-step explanation:

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3 years ago

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Simplify. 5 - [ - ( - 2)]

Nimfa-mama [501]

Answer:

Step-by-step explanation:

1. A - times a - equals a +, which means [-(-2)] equals (2)

2. 5- (2) equals 5 - 2

3. 5-2= 3

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A major metropolitan newspaper selected a simple random sample of 1,600 readers from their list of 100,000 subscribers.

Tpy6a [65]

Answer: $(0.36845,\ 0.43155)$

Step-by-step explanation:

Let p be the population proportion of readers who would like more coverage of local news.

As per given , we have

sample size :=1600

sample proportion : $\hat{p}=40\%=0.40$

The confidence interval for population proportion is given by :-

$\hat{p}\pm z^* \sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}$

From z-table ,

For 99% confidence interval the z-value is 2.576.

Substitute all the values in the above formula , we get

The 99% confidence interval for the proportion of readers who would like more coverage of local news as

$0.40\pm(2.576) \sqrt{\dfrac{0.40(1-0.40)}{1600}}$

$0.40\pm(2.576) \sqrt{\dfrac{0.24}{1600}}$

$0.40\pm(2.576) \sqrt{0.00015}$

$0.40\pm(2.576) (0.0122474487139)$

$0.40\pm0.03155$

$(0.40-0.03155,\ 0.40+0.03155)=(0.36845,\ 0.43155)$

Hence, the 99% confidence interval for the proportion of readers who would like more coverage of local news is $(0.36845,\ 0.43155)$ .

5 0

3 years ago

Please help me really quick please

Romashka-Z-Leto [24]

Answer:

1. 29.52

2. 69.39

Step-by-step explanation:

1. 9.4*3.14=29.52

2. 4.7*4.7=22.09

22.09*3.14= 69.39

6 0

3 years ago