Try this solution: Common view of the equation of the circle is (x-a)²+(y-b)²=r², where point (a;b) is centre of the circle, r - radius. 1. using the coordinates of the centre and point (2;13) it is possible to define the radius of the circle: r=√(5²+12²)=13; the equation is (x+3)²+(y-1)²=13² or (x+3)²+(y-1)²=169; 2. using the coordinates of the centre and the radius: (x-2)²+(y-4)²=6² or (x-2)²+(y-4)²=36.
