A 7.100 L sample of gas is cooled from 73.0 °C to a temperature at which its volume is 5.700 L. What is this new temperature? As

Question

Andrej [43]

3 years ago

15

A 7.100 L sample of gas is cooled from 73.0 °C to a temperature at which its volume is 5.700 L. What is this new temperature? As

sume no change in pressure of the gas.

Chemistry

1 answer:

arsen [322] · Answer 1 · 2022-06-30T19:18:13+03:00

The mew temperature of a sample of gas is calculated using Charles law formula

that is v1/T1 = V2/T2
V1= 7.100 L
T1=73 + 273 = 346 K
V2 = 5.700 L
T2=?

by making the T2 the subject of the formula
T2 =V2T1/V1

T2= 5.700 x 346/7.100 =277.8 K