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Olegator [25]
3 years ago
14

How does your reaction time to the voluntary action of your quadriceps in compare with your reaction time to the simple reaction

task in this project
Chemistry
1 answer:
slava [35]3 years ago
8 0

If we know what we are reading, reaction time to the simple reaction task in this project will be less than reaction time to the voluntary action of your quadriceps, however, if we are reading for the first time, reaction time to the simple reaction task in this project will be more than reaction time to the voluntary action of your quadriceps.

<h3><u>Explanation:</u></h3>

First, we need to know what is the reaction time. Reaction time is the amount of time it takes to respond to a stimulus. Now we will talk about voluntary and involuntary actions.

Voluntary action is an action that is thought of and consciously performed by the person. So we can say the person has full control over the situation. An involuntary action is one which occurs without the conscious choice of an organism. If the involuntary action occurred as a response to some stimulus it will be known as a reflex. If we compare the reaction time of voluntary action of our quadriceps and the simple reaction to the task given in the project, the reaction time could be less only if we have studied about the given question in the given task.

So the lines what we are reading will come to our mind involuntarily, but if we are talking about typing the answer the reaction time would be more as first, we have to form a structured sentence and then type it, so it will take more time.

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How many oxygen atoms are represented by the formula Fe(CIO4)3? iron(III) chlorate
zysi [14]

Answer:

12

Explanation:

the 4 by the element symbol O multiplied by the 3 on the outside of the parentheses

5 0
2 years ago
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What is the element that is in period 5 and group 3?
rjkz [21]

Answer:

Rubidium

Rubidium is the first element placed in period 5. 

6 0
3 years ago
The relative atomic mass of Chlorine is 35.45. Calculate the percentage abundance of the two isotopes of Chlorine, 35Cl and 37Cl
nata0808 [166]

Answer:

35Cl = 75.9 %

37Cl = 24.1 %

Explanation:

Step 1: Data given

The relative atomic mass of Chlorine = 35.45 amu

Mass of the isotopes:

35Cl = 34.96885269 amu

37Cl = 36.96590258 amu

Step 2: Calculate percentage abundance

35.45 = x*34.96885269 + y*36.96590258

x+y = 1  x = 1-y

35.45 = (1-y)*34.96885269 + y*36.96590258

35.45 = 34.96885269 - 34.96885269y +36.96590258y

0.48114731 = 1,99704989‬y

y = 0.241 = 24.1 %

35Cl = 34.96885269 amu = 75.9 %

37Cl = 36.96590258 amu = 24.1 %

3 0
2 years ago
You weigh out 0.1183 g of a complex salt to analyze for the percentage of cyanide ion in your complex salt. After dissolving the
Stels [109]

Answer:

25.35%

Explanation:

Again let me restate the the equation of the reaction;

H2O (ℓ) + 2 MnO4 - (aq) + 3 CN- (aq) → 2 MnO2 (s) + 3 CNO- (aq) + 2 OH- (aq)

Amount of potassium permanganate  reacted = 10.2/1000 * 0.08035 = 8.1957 * 10^-4 moles

If 2 moles of MnO4 - reacts with 3 moles of CN-

8.1957 * 10^-4 moles of MnO4 - reacts with 8.1957 * 10^-4 * 3/2

= 1.229 * 10^-3 moles of CN-

Mass of CN- reacted = 1.229 * 10^-3 moles of CN- * 26.02 g/mol

= 0.03 g

Hence, percentage of the cyanide = 0.03 g/0.1183 g * 100

= 25.35%

8 0
3 years ago
A graduated cylinder was filled with 25.0 mL of water. A solid object was immersed in the cylinder, raising the water level to 3
yawa3891 [41]

Answer:

Density of the object is 8759.494 grams/L

Explanation:

As we know density of an object is mass of the object divided by its volume

Given

Volume of the object is equal to the change in volume of water with in the cylinder when the object was immersed in water.

Hence, volume of object is equal to

32.9 -25 = 7.9 mL

Mass of the object is 69.2 grams

Density

= \frac{69.2}{7.9 *10^{-3}}\\= 8759.494 grams/L

Density of the object is 8759.494 grams/L

7 0
3 years ago
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