1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Dafna11 [192]
3 years ago
8

What are alkenes used to make?

Chemistry
2 answers:
gregori [183]3 years ago
8 0
They are used as starting materials in the syntheses of alcohols, plastics, laquers, detergents, and fuels. The most important alkenes for the chemical industry are ethene, propene and 1,3-butadiene.
evablogger [386]3 years ago
3 0

Answer:

By far the most important use of alkenes is in the making of plastics as plastics are used in almost everything.

Explanation:

Alkenes themselves aren't used much in everyday life however Alkenes are very important to industrial synthesis as it is relatively easy to turn them into other things.

Alkenes can be turned into polymers or plastics through addition reactions and the most common ethene is turned into everything from plastic bags to bottles.

Alkenes can also be turned into alcohols. most commonly propene is used as a feedstock to produce butanol and other products useful in industry or for production

Explanation:

Can you be my friend in here

You might be interested in
Predict the sign of enthalpy for reaction f+f=f2
guajiro [1.7K]
6+6=12


is your answer
6 0
3 years ago
Which of these events leaves small pieces of rocks in new places? (4 points)
icang [17]
A. deposition

this means that it was moved from one place to another and can be transported by ice, water, gravity, or wind.
5 0
2 years ago
A package contains 1.33 lb of ground round. If it contains 29% fat, how many grams of fat are in the ground round? The book is s
Effectus [21]

Answer:

To obtain the grams of fat that the ground round has, knowing that it weighs 1.33 pounds we must pass this value to grams. Since 1 pound equals 453.59 grams, 1.33 pounds equals 603.27 (453.59 x 1.33).

Now, to obtain 29 percent of 603.27, we must make the following calculation: 603.27 / 100 x 29, which gives a total of 174.94 grams.

In this way, your reasoning is correct and it is probably a mistake in the book.

6 0
3 years ago
Name of these two Alkanes
fgiga [73]
3-ethyl-5,6-dimethyloctane

3-ethyl-2,3-dimethylpentane
5 0
3 years ago
What must be the molarity of an aqueous solution of trimethylamine, (ch3)3n, if it has a ph = 11.20? (ch3)3n+h2o⇌(ch3)3nh++oh−kb
Stolb23 [73]

0.040 mol / dm³. (2 sig. fig.)

<h3>Explanation</h3>

(\text{CH}_3)_3\text{N} in this question acts as a weak base. As seen in the equation in the question, (\text{CH}_3)_3\text{N} produces \text{OH}^{-} rather than \text{H}^{+} when it dissolves in water. The concentration of \text{OH}^{-} will likely be more useful than that of \text{H}^{+} for the calculations here.

Finding the value of [\text{OH}^{-}] from pH:

Assume that \text{pK}_w = 14,

\begin{array}{ll}\text{pOH} = \text{pK}_w - \text{pH} \\ \phantom{\text{pOH}} = 14 - 11.20 &\text{True only under room temperature where }\text{pK}_w = 14 \\\phantom{\text{pOH}}= 2.80\end{array}.

[\text{OH}^{-}] =10^{-\text{pOH}} =10^{-2.80} = 1.59\;\text{mol}\cdot\text{dm}^{-3}.

Solve for [(\text{CH}_3)_3\text{N}]_\text{initial}:

\dfrac{[\text{OH}^{-}]_\text{equilibrium}\cdot[(\text{CH}_3)_3\text{NH}^{+}]_\text{equilibrium}}{[(\text{CH}_3)_3\text{N}]_\text{equilibrium}} = \text{K}_b = 1.58\times 10^{-3}

Note that water isn't part of this expression.

The value of Kb is quite small. The change in (\text{CH}_3)_3\text{N} is nearly negligible once it dissolves. In other words,

[(\text{CH}_3)_3\text{N}]_\text{initial} = [(\text{CH}_3)_3\text{N}]_\text{final}.

Also, for each mole of \text{OH}^{-} produced, one mole of (\text{CH}_3)_3\text{NH}^{+} was also produced. The solution started with a small amount of either species. As a result,

[(\text{CH}_3)_3\text{NH}^{+}] = [\text{OH}^{-}] = 10^{-2.80} = 1.58\times 10^{-3}\;\text{mol}\cdot\text{dm}^{-3}.

\dfrac{[\text{OH}^{-}]_\text{equilibrium}\cdot[(\text{CH}_3)_3\text{NH}^{+}]_\text{equilibrium}}{[(\text{CH}_3)_3\text{N}]_\textbf{initial}} = \text{K}_b = 1.58\times 10^{-3},

[(\text{CH}_3)_3\text{N}]_\textbf{initial} =\dfrac{[\text{OH}^{-}]_\text{equilibrium}\cdot[(\text{CH}_3)_3\text{NH}^{+}]_\text{equilibrium}}{\text{K}_b},

[(\text{CH}_3)_3\text{N}]_\text{initial} =\dfrac{(1.58\times10^{-3})^{2}}{6.3\times10^{-5}} = 0.040\;\text{mol}\cdot\text{dm}^{-3}.

8 0
3 years ago
Other questions:
  • 30,434 and 43,403 alike and difrente
    5·1 answer
  • Provide examples of physical weathering and chemical weathering in the chart below
    8·1 answer
  • Give an example of a 2 phase mixture and describe how you would separate the substances
    12·2 answers
  • During the lytic cycle, but not the lysogenic cycle, _____.
    5·1 answer
  • Where can you find hydraulic acid in your body what does it do
    13·1 answer
  • How do the bonds differ in<br> each type?
    12·2 answers
  • Fill in the chart to identify how scientists represent matter and chemical changes in matter.
    12·1 answer
  • Give the change in condition to go from a gas to a solid. Group of answer choices cool or increase pressure cool or reduce press
    14·1 answer
  • What else can copper react with?
    15·2 answers
  • If the sodium oxide (Na2O) in soda-lime glass was replaced by potassium oxide (K2O), this would result in . . .
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!