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morpeh [17]
3 years ago
5

Michael visited his grandparents.The total distance was 280 miles.By train,he could travel 90 miles per hour.By bus he could tra

vel 60 miles per hour. How much time could Michael save by taking the train?
Mathematics
1 answer:
lesya692 [45]3 years ago
4 0
Michael could save about 95 minutes by taking the train.
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What is 1/8÷9 in simplest form
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0.0138888888889 or

1/72​

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Create an equation that you can use in everyday life. Then solve it.
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2 years ago
(CO 4) In a sample of 8 high school students, they spent an average of 24.8 hours each week doing sports with a sample standard
AveGali [126]

Answer:  

(22.12, 27.48)

Step-by-step explanation:

Given : Significance level : \alpha: 1-0.95=0.05

Sample size : n= 8 , which is a small sample (n<30), so we use t-test.

Critical values using t-distribution: t_{n-1,\alpha/2}=t_{7,0.025}=2.365

Sample mean : \overline{x}=24.8\text{ hours}

Standard deviation : \sigma=3.2\text{ hours}

The confidence interval for population means is given by :-

\overline{x}\pm t_{n-1,\alpha/2}\dfrac{\sigma}{\sqrt{n}}

i.e. 24.8\pm(2.365)\dfrac{3.2}{\sqrt{8}}

24.8\pm2.67569206001\\\\\approx24.8\pm2.68\\\\=(24.8-2.68, 24.8+2.68)=(22.12, 27.48)

Hence, the 95% confidence interval, assuming the times are normally distributed.=  (22.12, 27.48)

6 0
2 years ago
Solve the equation.
lawyer [7]

Answer:

  • x=12
  • x=9

Step-by-step explanation:

1) Eliminate parentheses:

  0.1x +18.8 = -4 +2x

  22.8 = 1.9x . . . . . . . . . add 4 - 0.1x

  12 = x . . . . . . . . . . . . . divide by 1.9

__

2) Eliminate parentheses:

  -16 +4x = 0.8x +12.8

  3.2x = 28.8 . . . . . . . . add 16 - 0.8x

  x = 9 . . . . . . . . . . . . . .divide by 3.2

_____

<em>Comments on the solutions</em>

The expression we add in each case eliminates the constant on one side of the equation and the variable term on the other side. That leaves an equation of the form ...

  variable term = constant

We choose to eliminate the smaller variable term (the one with the coefficient farthest to the left on the number line). Then the constant we eliminate is the on on the other side of the equation. This choice ensures that the remaining variable term has a positive coefficient, tending to reduce errors.

__

You can work these problems by methods that eliminate fractions. Here, the fractions are decimal values, so are not that difficult to deal with. In any event, it is good to be able to work with numbers in any form: fractions, decimals, integers. It can save some steps.

7 0
2 years ago
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