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attashe74 [19]
4 years ago
9

Complete the place-value chart for the following number. Write its number name and tell the value of the underline digit.

Mathematics
2 answers:
daser333 [38]4 years ago
3 0
Six and three-hundred-twenty four thousands. The Number 2 is in the Hundreths place value.
DerKrebs [107]4 years ago
3 0

Answer:

Six and three hundred twenty-four thousandths.

Underline digit: 0.02; two-hundredths.

Step-by-step explanation:

We are asked to write the number name and tell the value of the underline digit.

6.3\underline{2}4

First of all, we will find place value of each digit.

Ones: 6

Tenths: 3

Hundredths: 2

Thousandths: 4

Therefore, our given number would be six and three hundred twenty-four thousandths.

Underline digit is at hundredths place, therefore, its value would be 0.02.

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Australian glitter ants reproduce so that their population doubles every 15 days. If there are 3 ants initially, the equation is
Firlakuza [10]

Answer:

  4.73%

Step-by-step explanation:

  y = 3×2^(t/15) = 3×(2^(1/15))^t = 3×1.0472941^t

In this form, ...

  1 +r = 1.0472941

  r = .0472941 ≈ 4.73%

The daily increase is about 4.73%.

5 0
3 years ago
An item was bought for £200. It was sold for £80. What was the percentage loss?
Agata [3.3K]

Answer:

0.6 or 60%.

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Find the area. See image below.
Burka [1]

Answer:

530 in ^2

Step-by-step explanation:

The figure given is a triangle

We use the formula for the area of a triangle

A = 1/2 bh where b is the length of the base and h is the height

      The height is perpendicular to the base( at 90 degrees)

A = 1/2 ( 26.5) * ( 40)

    = 530 in ^2

8 0
2 years ago
Read 2 more answers
Allison has three containers with 25 crayons in each. She also has four boxes of markers with 12 markers in each box. She gets 1
Advocard [28]

25x3=75
4x12=48
48-10=38

75 crayons and 38 markers
3 0
4 years ago
Is the function given by, (Picture Provided)
Sever21 [200]

Answer:

a. yes

Step-by-step explanation:

The given function is

f(x)=\left \{ {{3x-2,if\:x\le3} \atop {10-x,if\:x\:>\:3}} \right.

f(3)=\left \{ {{3(3)-2,if\:x\le3} \atop {10-3,if\:x\:>\:3}} \right.=7

\lim_{x \to 3^-} f(x)=3(3)-2=7

\lim_{x \to 3^+} f(x)=10-3=7

\Rightarrow \lim_{x \to 3} f(x)=7

Since;

\lim_{x \to 3} f(x)=f(3)

The function is continuous at x=3

7 0
3 years ago
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