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3 years ago

12

If f(x)=5x^0+4x^-3 then f(a)=?

1 answer:

devlian [24]3 years ago

4 0

X=a
f(a)=5(a^0)+4a^-3 a^0=1
=5(1)+4/a^3
=5+4/(a^3)

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The midpoint of \overline{\text{AB}}

Schach [20]

Answer:

<em>The coordinates of b are: B=(-7,-8)</em>

Step-by-step explanation:

We are given the coordinates of the midpoint of $\overline{\text{AB}}$ as M=(-5,-2).

We are also given the coordinates of A=(-3,4). The question requires us to calculate the coordinates of the other endpoint B.

Let (xb,yb) the coordinates of B. The coordinates of the midpoint can be calculated as follows:

$\displaystyle x_m=\frac{x_a+x_b}{2}$

$\displaystyle y_m=\frac{y_a+y_b}{2}$

We know xa=-3 and xm=-5. Solve the first equation for xb:

$2x_m=x_a+x_b\Rightarrow x_b=2x_m-x_a$

Substituting:

$x_b=2\cdot (-5)-(-3)=-10+3$

$x_b=-7$

We can solve the second equation for xb and get:

$y_b=2y_m-y_a$

Since ya=4 and ym=-2, then:

$y_b=2\cdot (-2)-(4)=-4-4$

$y_b=-8$

Thus, the coordinates of b are: B=(-7,-8)

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3 years ago

Write an equation of a circle that has the center at the origin and goes through (-3,-6)

dexar [7]

Answer:

$x^{2} +y^{2} = 45$

Step-by-step explanation:

General Equation of circle is

$(x-x_1)^{2} +(y-y_1)^{2} = r^{2}$ ----------- (1)

Here

$(x_1, y_1)= (0, 0)$

Radius r is distance from origin (x1, y1) to point (x2, y2)=(-3, -6)

$r=\sqrt{(x_2-x_1)^{2} + (y_2-y_1)^{2} }$

$r= \sqrt{(-3-0)^{2} + (-6-0)^{2} }$

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$x^{2} +y^{2} = 45$

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2 years ago

On a Friday evening a pizza shop had orders for 4 pepperoni, 97, and 335 cheese pizzas. If the 4 cooks each made an equal number

aksik [14]

Add the order of pizzas together and divide by four. Round your answer.

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3 years ago

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Write an recursive formula for An, the nth term of the sequence<br> 5, -2, -9,

oksian1 [2.3K]

Given:

The given sequence is:

$5,-2,-9,...$

To find:

The recursive formula for $a_n$ , the nth term of the sequence.

Solution:

We have,

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$-9-(-2)=-7$

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$a_n=a_{n-1}+d$

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Step-by-step explanation:

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