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Juliette [100K]
3 years ago
7

if you divide a five-digit number by a one-digit number, what is the largest possible remainder you can get ?

Mathematics
2 answers:
solmaris [256]3 years ago
6 0
99999/8 has a remainder of 7
mihalych1998 [28]3 years ago
4 0
The largest remainder is when you divide by 9 
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PLEASE HELPPPPPPP
Fed [463]

Answer:

Molar mass = 254.60g/mol

Step-by-step explanation:

Mass = 8.02g

Volume = 812mL = 0.812L

Pressure (P) = 0.967atm

Temperature of the gas = 30°C = (30 + 273.15)K = 303.15K

Molecular weight = ?

To solve this question, we'll have to use ideal gas equation, PV = nRT

P = pressure of the gas

V = volume of the gas

n = number of moles of the gas

R = ideal gas constant = 0.082J/mol.K

T = temperature of the gas

PV = nRT

n = PV / RT

n = (0.967 * 0.812) / (0.082 * 303.15)

n = 0.7852 / 24.8583

n = 0.0315 moles

Number of moles = mass / molarmass

Molarmass = mass / number of moles

Molar mass = 8.02 / 0.0315

Molar mass = 254.60g/mol

The molar mass of the gas is 254.60g/mol

3 0
3 years ago
Please help number 5 thank you
Triss [41]

Answer    2,290 of total sheets of paper she bought.

Step-by-step explanation:

65x36=2340

subtract 50 for the black pages that she did not use.

2340-50=2,290

6 0
3 years ago
Read 2 more answers
The price of a loaf of bread increases by $0.25 each week
krok68 [10]

The question didn't make sense, could you add more to it?

4 0
3 years ago
Read 2 more answers
What is the length of XZ
Artemon [7]

Answer:

XZ=13\ units

Step-by-step explanation:

we know that

In the right triangle of the figure XYZ

Applying the Pythagorean Theorem

XZ^2=XY^2+YZ^2

substitute the given values

XZ^2=12^2+5^2

XZ^2=144+25

XZ^2=169

square root both sides

XZ=13\ units

6 0
3 years ago
A right circular cylinder is inscribed in a sphere with diameter 4cm as shown. If the cylinder is open at both ends, find the la
SOVA2 [1]

Answer:

8\pi\text{ square cm}

Step-by-step explanation:

Since, we know that,

The surface area of a cylinder having both ends in both sides,

S=2\pi rh

Where,

r = radius,

h = height,

Given,

Diameter of the sphere = 4 cm,

So, by using Pythagoras theorem,

4^2 = (2r)^2 + h^2   ( see in the below diagram ),

16 = 4r^2 + h^2

16 - 4r^2 = h^2

\implies h=\sqrt{16-4r^2}

Thus, the surface area of the cylinder,

S=2\pi r(\sqrt{16-4r^2})

Differentiating with respect to r,

\frac{dS}{dr}=2\pi(r\times \frac{1}{2\sqrt{16-4r^2}}\times -8r + \sqrt{16-4r^2})

=2\pi(\frac{-4r^2+16-4r^2}{\sqrt{16-4r^2}})

=2\pi(\frac{-8r^2+16}{\sqrt{16-4r^2}})

Again differentiating with respect to r,

\frac{d^2S}{dt^2}=2\pi(\frac{\sqrt{16-4r^2}\times -16r + (-8r^2+16)\times \frac{1}{2\sqrt{16-4r^2}}\times -8r}{16-4r^2})

For maximum or minimum,

\frac{dS}{dt}=0

2\pi(\frac{-8r^2+16}{\sqrt{16-4r^2}})=0

-8r^2 + 16 = 0

8r^2 = 16

r^2 = 2

\implies r = \sqrt{2}

Since, for r = √2,

\frac{d^2S}{dt^2}=negative

Hence, the surface area is maximum if r = √2,

And, maximum surface area,

S = 2\pi (\sqrt{2})(\sqrt{16-8})

=2\pi (\sqrt{2})(\sqrt{8})

=2\pi \sqrt{16}

=8\pi\text{ square cm}

4 0
3 years ago
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