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3 years ago

if you divide a five-digit number by a one-digit number, what is the largest possible remainder you can get ?

Mathematics

2 answers:

solmaris [256]3 years ago

6 0

99999/8 has a remainder of 7

mihalych1998 [28]3 years ago

4 0

The largest remainder is when you divide by 9

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PLEASE HELPPPPPPP

Fed [463]

Answer:

Molar mass = 254.60g/mol

Step-by-step explanation:

Mass = 8.02g

Volume = 812mL = 0.812L

Pressure (P) = 0.967atm

Temperature of the gas = 30°C = (30 + 273.15)K = 303.15K

Molecular weight = ?

To solve this question, we'll have to use ideal gas equation, PV = nRT

P = pressure of the gas

V = volume of the gas

n = number of moles of the gas

R = ideal gas constant = 0.082J/mol.K

T = temperature of the gas

PV = nRT

n = PV / RT

n = (0.967 * 0.812) / (0.082 * 303.15)

n = 0.7852 / 24.8583

n = 0.0315 moles

Number of moles = mass / molarmass

Molarmass = mass / number of moles

Molar mass = 8.02 / 0.0315

Molar mass = 254.60g/mol

The molar mass of the gas is 254.60g/mol

3 0

3 years ago

Please help number 5 thank you

Triss [41]

Answer 2,290 of total sheets of paper she bought.

Step-by-step explanation:

65x36=2340

subtract 50 for the black pages that she did not use.

2340-50=2,290

6 0

3 years ago

Read 2 more answers

The price of a loaf of bread increases by $0.25 each week

krok68 [10]

The question didn't make sense, could you add more to it?

4 0

3 years ago

Read 2 more answers

What is the length of XZ

Artemon [7]

Answer:

$XZ=13\ units$

Step-by-step explanation:

we know that

In the right triangle of the figure XYZ

Applying the Pythagorean Theorem

$XZ^2=XY^2+YZ^2$

substitute the given values

$XZ^2=12^2+5^2$

$XZ^2=144+25$

$XZ^2=169$

square root both sides

$XZ=13\ units$

6 0

3 years ago

A right circular cylinder is inscribed in a sphere with diameter 4cm as shown. If the cylinder is open at both ends, find the la

SOVA2 [1]

Answer:

$8\pi\text{ square cm}$

Step-by-step explanation:

Since, we know that,

The surface area of a cylinder having both ends in both sides,

$S=2\pi rh$

Where,

r = radius,

h = height,

Given,

Diameter of the sphere = 4 cm,

So, by using Pythagoras theorem,

$4^2 = (2r)^2 + h^2$ ( see in the below diagram ),

$16 = 4r^2 + h^2$

$16 - 4r^2 = h^2$

$\implies h=\sqrt{16-4r^2}$

Thus, the surface area of the cylinder,

$S=2\pi r(\sqrt{16-4r^2})$

Differentiating with respect to r,

$\frac{dS}{dr}=2\pi(r\times \frac{1}{2\sqrt{16-4r^2}}\times -8r + \sqrt{16-4r^2})$

$=2\pi(\frac{-4r^2+16-4r^2}{\sqrt{16-4r^2}})$

$=2\pi(\frac{-8r^2+16}{\sqrt{16-4r^2}})$

Again differentiating with respect to r,

$\frac{d^2S}{dt^2}=2\pi(\frac{\sqrt{16-4r^2}\times -16r + (-8r^2+16)\times \frac{1}{2\sqrt{16-4r^2}}\times -8r}{16-4r^2})$

For maximum or minimum,

$\frac{dS}{dt}=0$

$2\pi(\frac{-8r^2+16}{\sqrt{16-4r^2}})=0$

$-8r^2 + 16 = 0$

$8r^2 = 16$

$r^2 = 2$

$\implies r = \sqrt{2}$

Since, for r = √2,

$\frac{d^2S}{dt^2}=negative$

Hence, the surface area is maximum if r = √2,

And, maximum surface area,

$S = 2\pi (\sqrt{2})(\sqrt{16-8})$

$=2\pi (\sqrt{2})(\sqrt{8})$

$=2\pi \sqrt{16}$

$=8\pi\text{ square cm}$

4 0

3 years ago