What is the measurement of loudness of sounds
1 answer:
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Answer:
The magnitude of the acceleration is 4.2 m/s²
Explanation:
Given;
initial velocity of the powerful sports car, u = 0
final velocity of the powerful sports car, v = 25 m/s
time of motion, t = 6 seconds
Acceleration = Δv / Δt
Δv is change in velocity
Δt is change in time
The magnitude of the acceleration of the powerful sports car during the motion is given by;
Therefore, the magnitude of the acceleration is 4.2 m/s²
Answer:
a) t= 4.81 s,and t= 23.51.
b)d=6.88 m
c)v=4.8 m/s
Explanation:
Acceleration of train ,a= 0.6 m/s²
u = 0 m/s
Your speed ,V= 8.5 m/s
Lets take after t time he you catch the train
Distance travel by train in t time
----------1
d= V ( t- 4)
d= 8.5 ( t- 4) --------2
By equating equation 1 and 2
0.3 t² = 8.5 ( t- 4)
0.3 t² -8.5 t + 34 = 0
t= 4.81 s and t= 23.51
It means that you will catch train after t= 4.81 s,and t= 23.51.
t=23.51 sec means that you will catch the train after 23.51 sec also because acceleration of train is low.
Distance travel
d= 8.5 ( t- 4)
t= 4.81 s
d= 8.5 ( 4.81- 4) m
d=6.88 m
Lets speed = v
0.3 t² = v ( t- 4)
0.3 t² - v t + 4 v = 0
To have one solution
D= 0 Should be zero.
v²- 4 x 0.3 x 4 v
v = 4 x 0.3 x 4
v=4.8 m/s