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olya-2409 [2.1K]
3 years ago
13

The wavelength and energy of a wave are inversely proportional. Based on this, which wave listed would have the LOWEST energy.

Physics
2 answers:
spayn [35]3 years ago
5 0
D because it has the lowest wavelength, meaning the wave is the longest. Its crest are more spaced out creating lower energy.  The smaller distance between the crests equals the higher the sound. Creating higher energy.

I am 95% sure this is right. Very sorry if it isn't.
Hope it helps. ;3
serg [7]3 years ago
4 0

Answer:

D) wave with wavelength of 600 km

Explanation:

If the wavelength and energy of a wave are inversely proportional, then a high wavelength corresponds to a low energy, and low wavelength corresponds to a high energy. So, the lowest energy correspond the highest wavelength. From the options that is option D. Remember that 600 km > 600 m > 600 cm > 600 mm

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zhenek [66]

Answer:

c. dioptre that's the answer.

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What is the original source of hydroelectric energy
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3 years ago
Determine the critical crack length for a through crack contained within a thick plate of 7150-T651 aluminum alloy that is in un
Mila [183]

Explanation:

Formula to determine the critical crack is as follows.

          K_{IC} = \gamma \sigma_{f} \sqrt{\pi \times a}

  \gamma = 1,     K_{IC} = 24.1

  [/tex]\sigma_{y}[/tex] = 570

and,   \sigma_{f} = 570 \times \frac{3}{4}

                       = 427.5

Hence, we will calculate the critical crack length as follows.

      a = \frac{1}{\pi} \times (\frac{K_{IC}}{\sigma_{f}})^{2}

        = \frac{1}{3.14} \times (\frac{24.1}{427.5})^{2}

       = 10.13 \times 10^{-4}

Therefore, largest size is as follows.

            Largest size = 2a

                                 = 2 \times 10.13 \times 10^{-4}

                                 = 20.26 \times 10^{-4}

Thus, we can conclude that the critical crack length for a through crack contained within the given plate is 20.26 \times 10^{-4}.

4 0
3 years ago
The electromagnetic wave that delivers a cellular phone callto
spin [16.1K]

Answer:

E=2.41\cdot 10^{-5} J

Explanation:

The intensity of an electromagnetic wave can be expressed in terms of the magnetic field using the next relationship:

I_{average}=\frac{cB_{0}^{2}}{2\mu_{0}} (1)

  • c is the speed of light (3*10⁸ m/s)
  • μ₀ is the permeability of free space (in vacuum ) (1.26*10⁻⁶ N/A²)
  • B₀ is the magnetic field

I_{average}=\frac{3\cdot 10^{8}(1.5\cdot 10^{-10})^{2}}{2\cdot 1.26\cdot 10^{-6}}

I_{average}=2.68\cdot 10^{-6} W/m^{2}

Now, let's define the relationship between power (P) and average intensity (I).

I_{average}=\frac{P}{A}

  • P is the power
  • A is the area crossed

So we can calculate the power.

P=I_{average}\cdot A=2.68\cdot 10^{-6}\cdot 0.20=5.37\cdot 10^{-7} W

Finally, energy is the product of P times time, so:

E=P\cdot t=5.37\cdot 10^{-7} \cdot 45=2.41\cdot 10^{-5} J

I hope it helps you!

5 0
3 years ago
The security alarm on a parked car goes off and produces a frequency of 769 Hz. The speed of sound is 343 m/s. As you drive towa
uysha [10]

Answer:

Explanation:

ASSUMING your speed is constant

f₀ = f(v + vo)/(v + vs)

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69.5 = (769(343 + vo)/(343 + 0)) - (769(343 - vo)/(343 + 0))

69.5 = 769(2vo/343)

  vo = 15.5 m/s

6 0
2 years ago
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