The wavelength and energy of a wave are inversely proportional. Based on this, which wave listed would have the LOWEST energy.

2 answers:

5 0

D because it has the lowest wavelength, meaning the wave is the longest. Its crest are more spaced out creating lower energy. The smaller distance between the crests equals the higher the sound. Creating higher energy.

I am 95% sure this is right. Very sorry if it isn't.
Hope it helps. ;3

serg [7]4 years ago

4 0

Answer:

D) wave with wavelength of 600 km

Explanation:

If the wavelength and energy of a wave are inversely proportional, then a high wavelength corresponds to a low energy, and low wavelength corresponds to a high energy. So, the lowest energy correspond the highest wavelength. From the options that is option D. Remember that 600 km > 600 m > 600 cm > 600 mm

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how does distance change when the amount of effort force is increasesd while the amount of work done remains the same?

nlexa [21]

Could you supply u with some answer choices please?

8 0

4 years ago

ehidna [41]

Answer:

$a = -1.6\ m/s^2$

Explanation:

<u>Accelerated Motion</u>

It occurs when an object changes its speed over time. If the changes in speed are uniform, then the acceleration is constant, positive if the speed increases, negative if the speed decreases.

The acceleration is calculated as follows:

$\displaystyle a=\frac{v_f-v_o}{t}$

The aeroplane starts with a speed of vo=62 m/s and reaches a speed of vf=6 m/s in t=35 s.

The acceleration is:

$\displaystyle a=\frac{6-62}{35}=-\frac{56}{35}$

$\mathbf{a = -1.6\ m/s^2}$

3 0

3 years ago

In the diagram, 91, 92, and q3 are in a straight line. Each of these particles has a charge of -2.35 x 10-6 C. Particles q₁ and

Strike441 [17]

The net force on particle q₃ is 6.2128125 N.

<h3>What is electrostatic force?</h3>

The electrostatic force F between two charged objects placed distance apart is directly proportional to the product of the magnitude of charges and inversely proportional to the square of the distance between them.

F = kq₁q₂/d²

where k = 9 x 10⁹ N.m²/C²

Given is the diagram in which each of the particles has a charge of -2.35 x 10⁻⁶ C. Particles q₁ and q₂ are separated by 0.100 m and particles q₂ and q₃ are separated by 0.100 m.

Force acting on q₃ due to q₁

F₃₁ = 9 x 10⁹ x (-2.35 x 10⁻⁶)²/(0.1)²

F₃₁ = 4.97025 N(in right direction)

Force acting on q₃ due to q₂

F₃₂ = 9 x 10⁹ x (-2.35 x 10⁻⁶)²/(0.1+0.1)²

F₃₂ = 1.2425 N (in right direction)

Net force acting on particle q₃ is

F₃ = F₃₁ +F₃₂

F₃ = 4.97025 N + 1.2425 N

F₃ = 6.2128125 N

Thus the net force on a charged particle is 6.2128125 N to the right.

Learn more about electrostatic force.