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sesenic [268]
3 years ago
7

How much salt (nacl) is carried by a river flowing at 30.0 m3/s and containing 50.0 mg/l of salt? give your answer in kg/day?

Physics
1 answer:
slamgirl [31]3 years ago
7 0
Answer: 129,600kg/day
In this question, you are given the river flow (30m3/s) and the salt concentration. Then to determine the amount of salt carried, you simply need to multiply the flow with concentration. Be careful because the unit in this question is different and need to be converted. The equation would be:

Salt = river flow x salt concentration
Salt = 30m3/s x 1000L/m3 x 50mg/L = 1,500,000mg/second

Then convert it into kg/day
Salt= 1,500,000mg/second x 10^-6 kg/mg x (3600 second/hour) x (24 hour/day)= 129,600kg/day
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8 0
3 years ago
If a resistor draws 1.2 x 10^-3 a of current from a 12 v battery, then what is the value of the resistor?
bixtya [17]
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4 years ago
Gerry is looking at salt under a powerful microscope and notices a crystalline structure. What can be known about the salt sampl
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2 years ago
What is the potential difference per unit length between two infinitely long concentric cylindrical shells with inner radius 1.5
Vinil7 [7]

Answer:

165.8 V/m

Explanation:

The capacitance of a long concentric cylindrical shell of length, L and inner radius, a and outer radius, b is C = 2πε₀L/㏑(b/a)

Since the charge on the cylindrical shells, Q = CV where V = the potential difference across the capacitor(which is the potential difference between the concentric cylindrical shells)

V = Q/C

V = Q ÷ 2πε₀L/㏑(b/a)

V = Q㏑(b/a)/2πε₀L

So, the potential difference per unit length V' is

V' = V/L = Q㏑(b/a)/2πε₀

Given that a = inner radius = 1.5 cm, b = outer radius = 5.6 cm and Q = 7.0 nC = 7.0 × 10⁻⁹ C and ε₀ = 8.854 × 10⁻¹² F/m substituting the values of the variables into the equation, we have

V' = Q㏑(b/a)/2πε₀

V' = 7.0 × 10⁻⁹ C㏑(5.6 cm/1.5 cm)/(2π × 8.854 × 10⁻¹² F/m)

V' = 7.0 × 10⁻⁹ C㏑(3.733)/(55.631 × 10⁻¹² F/m)

V' = 7.0 × 10⁻⁹ C × 1.3173/(55.631 × 10⁻¹² F/m)

V' = 9.2211 × 10⁻⁹ C/(55.631 × 10⁻¹² F/m)

V' = 0.16575 × 10³ V/m

V' = 165.75 V/m

V' ≅ 165.8 V/m

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3 years ago
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Read 2 more answers
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