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3 years ago

Indica si las siguientes acciones son el resultado de un efecto estatico o dinamico de una fuerza.

Physics

1 answer:

Oduvanchick [21]3 years ago

8 0

Answer:

Sabemos por definición que la fuerza es lo que es capaz de producir cambios o deformaciones en un cuerpo y a esto se denomina efecto estático y cuando la alteración ejerce movimiento o reposo se denomina efecto dinámico, con esta base resolvemos que:

-estirar un muelle: efecto estatico

- devolver una volea: efecto dinámico

- aplastar la plastilina: efecto estático

- empujar el carro del supermercado: efecto dinámico

- inflar un globo: efecto estático

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3 years ago

A girl and her bicycle have a total mass of 40 kg. At the top of the hill her speed is 5.0 m/s. The hill is 10 m high and 100 m

Serhud [2]

Answer:

v = 11 m/s is her final speed

Explanation:

work done by gravity = m g Δh = 40×9.8×10 = 3920 Joules

Work done by friction = - force×distance = - 20×100 = - 2000 Joules

[minus sign because friction force is opposite to the direction of motion]

Initial K.E. = (1/2) m u^2 = (1/2) × 40 × 5^2 = 500 Joules

Now, by work energy theorem

Work done = change in kinetic energy.

Final K.E. = initial K.E. + total work = 500 + 3920 - 2000 = 2420 Joules

Now, Final K.E. = (1/2) m v^2 [final speed being v= speed at the bottom]

⇒ 2420 = (1/2)×40×v^2

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3 years ago

A cyclist makes the following trip along two vectors; he travels 9km to the north and then travels 6km to the east

elena-14-01-66 [18.8K]

Answer:

Final distance from the origin: 10.82 km. the vector points as shown in the attached image.

Angle with respect to the east: $56.31^o$

Explanation:

Please refer to the attached image. The cyclist's trip is indicated with the green arrows (9 km to the north followed by 6 km to the east.

So his final position is at the tip of this last vector, and indicated by the orange vector drawn form the point where the trip starts to the cyclist's final location.

We observe that this orange vector is in fact the hypotenuse of a right angle triangle, and we can estimate the distance from the origin by the Pythagorean theorem:

$d=\sqrt{9^2+6^2} \\d=\sqrt{81+36} \\d=\sqrt{117} \\d=10.82 \,\,km$

Notice that this is NOT the actual number of km that the cyclist pedaled to reach the final point.

Now, to find the value of the angle $\theta$ , we need to use trigonometry, and in particular the tangent function gives us the ratio between the side of the triangle "opposite" to the angle, divided the side "adjacent" to the angle:

$tan(\theta)=\frac{opp}{adj} \\tan(\theta)=\frac{9}{6}\\tan(\theta)=\frac{3}{2}\\$

Now we can find the value of the angle by using the arctan function:

$tan(\theta)=\frac{3}{2} \\\theta=arctan(\frac{3}{2} )\\\theta= 56.31^o$

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3 years ago