The estimate of how many stars are in a galaxy is 100 thousand million
Answer:
7,790.38 m/s
Explanation:
Given the following :
What linear speed must an Earth satellite have to be in a circular orbit at an altitude of 203 km above Earth's surface
Altitude = 203 km
Using the formula :
V = √GM/r
Where G = gravitational constant =6.67×10^-11
Kindly check attached picture for detailed explanation.
To determine the relative age of different rocks, geologists start with the assumption that unless something has happened, in a sequence of sedimentary rock layers, the newer rock layers will be on top of older ones. This is called the Rule of Superposition. ... With absolute age dating, you get a real age in actual
Answer:
Conduction, convection, and radiation
Explanation:
Conduction is the process in which energy is transferred from a hot body to a cooler body. Convection is a process by which heat is transferred as a result of the movement of heated fluid in the form of air or water. Radiation refers to the transmission of energy through a material medium.
Based on the information provided, a lava lamp could be used to provide an example of conduction, convection, and radiation.
Answer:
H / R = 2/3
Explanation:
Let's work this problem with the concepts of energy conservation. Let's start with point P, which we work as a particle.
Initial. Lowest point
Em₀ = K = 1/2 m v²
Final. In the sought height
= U = mg h
Energy is conserved
Em₀ =
½ m v² = m g h
v² = 2 gh
Now let's work with the tire that is a cylinder with the axis of rotation in its center of mass
Initial. Lower
Em₀ = K = ½ I w²
Final. Heights sought
Emf = U = m g R
Em₀ =
½ I w² = m g R
The moment of inertial of a cylinder is
I =
+ ½ m R²
I= ½
+ ½ m R²
Linear and rotational speed are related
v = w / R
w = v / R
We replace
½
w² + ½ m R² w² = m g R
moment of inertia of the center of mass
= ½ m R²
½ ½ m R² (v²/R²) + ½ m v² = m gR
m v² ( ¼ + ½ ) = m g R
v² = 4/3 g R
As they indicate that the linear velocity of the two points is equal, we equate the two equations
2 g H = 4/3 g R
H / R = 2/3