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3 years ago

What would happen to life on earth if all the plants died? plz help

Physics

2 answers:

DaniilM [7]3 years ago

8 0

Answer:

If all the plants on earth died,, then we would have no oxygen and all life would die too :(

Explanation:

mooooo :(

denis-greek [22]3 years ago

4 0

Answer:

we would have no oxygen and barely any water.

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What type of structure is the cytoplasm? I Will mark as brainiest if right

Irina-Kira [14]

145,600 it equals 145,600 so you put down the zeros

4 0

3 years ago

The mass of the man is 86 kg. What is the force of friction that slowed him down? Use the equation for Newton’s second law, F =

9966 [12]

F=ma
Since m=86kg
a of free falling = 9.8m/s
=> F = 86*9.8m/s= 842.8N

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3 years ago

A uniform marble rolls down a symmetric bowl, starting from rest at the top of the left side. The top of each side is a distance

statuscvo [17]

Answer:

$h' = \dfrac{5}{7}h$

Explanation:

To find how far will the smooth side will the marble go in the upper direction, measured vertically from the bottom (leave your answer in terms of h)?

From the given information:

The potential energy for the marble starting at rest is:

PE = m*g*h

In the bottom of the bowl; the marble exhibit a linear and rotational K.E

$K.E_{total} = K.E _{linear} + K.E _{rot}$

$K.E_{total} = \dfrac{1}{2}mv^2+I\omega^2$

$K.E_{total} = \dfrac{1}{2}mv^2+ \dfrac{1}{2}( \dfrac{2}{5}mR^2) ( \dfrac{v}{R})^2$

$K.E_{total} = \dfrac{1}{2}mv^2+ \dfrac{1}{5}mv^2$

$K.E_{total} = (\dfrac{5+2}{10})mv^2$

$K.E_{total} = \dfrac{7}{10}mv^2$

By applying Conservation of energy, The Total Energy occurring in the marble when it started at rest is the same as the total energy when it gets to the midpoint in the bowl.

i.e.

$P.E = K.E_{total}$

$mgh = \dfrac{7}{10 }mv^2$

10 × mgh= 7mv²

making v² the subject of the formula, we get:

$v^2 = \dfrac{10}{7 }gh$

Let us remember that the rotational K.E occurring at the midpoint of the bowl is still unchanged at the time the marble is moving to the left side.

Thus, by applying the Conservation of energy balance:

The linear K.E at the midpoint = The P.E of the marble

∴

$\dfrac{1}{2}mv^2 = mgh'$

Making h' the subject, we get:

mv² = 2mgh'

Divide both sides by m

v² = 2gh'

Recall that $v^2 = \dfrac{10}{7 }gh$

$\dfrac{10}{7} gh = 2gh'$

10 gh = 14 gh'

Divide both sides by 2g

5h = 7h'

$h' = \dfrac{5}{7}h$

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3 years ago

Two 100 ohm resistors are connected in series and they are connected to a 1.5V battery. (a) What is the total resistance? (b) Wh

iogann1982 [59]

Answer: a = 200 Ω, b = 7.5 mA

Explanation:

Re = 100 + 100 = 200 Ω

I = E/R = 1.5/200 = 0.0075 A

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3 years ago

Start at the beginning of the moon orbit video, which shows the sun and part of earth's orbit. if we wanted to show the moon's o

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3 years ago