Answer:
<< how fast is it going when it was caught? >>
Working formula is
Vf^2 - Vo^2 = 2gH
where
Vf = velocity of stone when it was caught
Vo = initial velocity = 20 m/sec.
g = acceleration due to gravity = 9.8 m/sec^2 (constant)
H = height at which stone was caught = 5 meters (given)
Substituting values,
Vf^2 - 20^2 = 2(9.8)(-5)
Vf^2 = 400 - 98
Vf^2 = 302
Vf = 17.38 m/sec.
<< how long did the trip take? >>
Formula is
H = Vo(T) + (1/2)gT^2
-5 = -20T + (1/2)(9.8)T^2
4.9T^2 - 20T + 5 = 0
Using the quadratic formula,
T = 3.81 seconds
Hope this helps.
Answer:
A velocity of
Explanation:
Since the magnitude of the vector is equal to the magnitude of velocity, velocity of the 2 cm vector represents a velocity of $10\times 2= 20 \: km/h$.
Answer:
45° should be the correct one