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natulia [17]
3 years ago
7

find the elasped time from 10:11 to 5:34 pls show your work . A) 5hrs and 37mins , B) 4hrs , C) 5h 23mins , D) 4hr 37mins

Mathematics
1 answer:
Bingel [31]3 years ago
8 0
The question as you wrote it doesn't fit the answers. However, one of the answers fits if you meant
"elapsed time from 5:34 to 10:11".

There are many ways to do this. Try first taking the time from 5:34 to 6:11, and after that finding the time from 6:11 to to 10:11.

In a way, 6:00 is the same thing as 5:60. Add 11 to that and you can see that 6:11 is the same as 5:71. Now that you have an easy way to find the time from 5:34 to 6:11.
6:11 - 5:34 isn't easy.
But 5:71 - 5:34 is quite easy. 71 - 34 is 37.

So, from 5:34 to 6:11 there are 37 minutes.

Now the easy part, finding the time from 6:11 to 10:11. Since the minutes are the same, just subtract the hours. 10 - 6 = 4 hours.

Now you have the hours and minutes, which number 4 hours and 37 minutes.
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Circle A was translated 3 units to the left and 4 units up to create Circle B. Which rule describes the translation that was app
kifflom [539]

Answer:

B = (x - 3, y + 4)

Step-by-step explanation:

Given

Represent the coordinates of circle A with (x,y)

<u>Translation</u>

Left = 3 units

Up = 4 units

Required

Determine the coordinates of B

When a point (x,y) is translated by h units left, the new point is: (x - h, y)

When a point (x,y) is translated by b units up, the new point is: (x, y + b)

So, when circle A is completely translated to B, the new points of B is:

B = (x - h, y + b)

In this case:

h = 3\ and\ b = 4

So:

B = (x - 3, y + 4)

4 0
3 years ago
Obtain an expression that looks like this: 25+ 4 А B. X(S) = + s(s +6) S +6 S
Svetlanka [38]

Answer:

A = \frac{2}{3}

B = \frac{4}{3}

Step-by-step explanation:

Given

X(s) = \frac{2s + 4}{s(s +6)}= \frac{A}{s} + \frac{B}{s + 6}

Required

Find A and B

The expression can be rewritten as

\frac{2s + 4}{s(s +6)}= \frac{A}{s} + \frac{B}{s + 6}

Take LCM of the right hand side

\frac{2s + 4}{s(s +6)}= \frac{A(s + 6 )+ Bs}{s(s +6)}

Cancel out the denominators

2s + 4 = A(s + 6) + Bs

Open Bracket

2s + 4 = As + 6A+Bs

Reorder

2s + 4 = As +Bs+ 6A

By direct comparison:

2s = As + Bs

4 = 6A

Solving 2s = As + Bs

Divide through by s

2 = A + B

Solve for A in 4 = 6A

\frac{4}{6} = A

A = \frac{4}{6}

A = \frac{2}{3}

Substitute \frac{2}{3} for A in 2 = A + B

2 = \frac{2}{3} + B

B = 2 - \frac{2}{3}

LCM

B = \frac{6 - 2}{3}

B = \frac{4}{3}

4 0
3 years ago
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