0.0038 is the probability that the code is 9Z.
<u>Step-by-step explanation:</u>
Here we have , A code consists of a digit chosen from 0 to 9 followed by a letter of the alphabet. We need to find What is the probability that the code is 9Z . Let's find out:
A code consists of a digit between 0-9 , i.e. there are 10 choices . And followed by a letter i.e. from A-Z having 26 choices ! So combinations possible are :
0{A-Z}=26
1{A-Z} = 26
2{A-Z} = 26
3{ A-Z}=26
.......
9{A-Z}=26 or ,
⇒ 10(26)
⇒ ![260](https://tex.z-dn.net/?f=260)
Now , 9Z is one combination ! So , probability :
⇒ ![\frac{1}{260}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B260%7D)
⇒ ![0.0038](https://tex.z-dn.net/?f=0.0038)
Therefore , 0.0038 is the probability that the code is 9Z.
Answer:
B
Step-by-step explanation:
We know that
Any point <span>(x,y)</span> on the parabola is equidistant from the focus and the directrix
Therefore,
focus (0,4) and directrix of y=2
<span>√[<span>(x−0)</span></span>²+(y−4)²]=y−(2)
<span>√[x</span>²+(y-4)²]=y-2
x²+(y-4)²=(y-2)²
x²+y²-8y+16=y²-4y+4
x²=4y-12-----> 4y=x²+12----->y= (x²/4)+3
the answer is
y= (x²/4)+3
Answer:
Because alternate exterior angles are congruent
Step-by-step explanation: