Answer:
2nd answer option
Step-by-step explanation:
the domain is the interval or set of valid x values. the range is the same for valid y values.
so, what is the smallest x value we see in the functional graph ?
x = 0
there is no functional value for any x smaller than that.
and then the function goes on and on to the right in all eternity. that means it goes to infinity.
so, domain = [0, infinity)
please consider the round bracket at the end, because "infinity" is not a number.
now for the range and the y values.
in this case I start to ask for the largest y value.
y = 4
for no x value do we get a larger y value.
but it goes down and down in all eternity, going also to infinity, but -infinity (down is negative for y).
so, the range = (-infinity, 4]
"-infinity" is also not a number and therefore not included (hence the round bracket).
19. 4/6 or 2/3 (lowest term) or 2:3 in ratio
20. 2/3 or 2:3 in ratio
21. 5/12 or 5:12 in ratio
22. 14
To get geometric mean, multiply the numbers then get the square root of the product (if there are two numbers), cube root (if there are three numbers), and so on. In this case, 7*28 = 196; √196 = 14
23. 10 ft : 2.5 ft.
Convert the values so that it will be similar. In this case, 30 inches is converted to ft.
24. 24 is the Perimeter of ABCDE.
ABCDE and FGHJK are similar shapes. Similar shapes have proportional measurements.
Now compute for the sides of ABCDE.
AB = 4; BC = ?; CD = ?; DE = ?; EA = ?
AB + BC + CD + DE + EA
4 + 4 + 5 + 6 + 5 = 24
Find BC:
AB/BC = FG/GH
4/BC = 8/8
8BC = 32
BC = 4
Find CD:
BC/CD = GH/HJ
4/CD = 8/10
8CD = 40
CD = 5
Find DE:
CD/DE = HJ/JK
5/DE = 10/12
10DE = 60
DE = 6
Find EA
DE/EA = JK/KF
6/EA = 12/10
12EA = 60
EA = 5
Answer:
Wait... that's my name... whatever, here is the answer XD
Step-by-step explanation:
c+9.75=20.75 is the answer :D
Cost of his ticket is $20.75
43/12 can be
3 7/12
Hope this helps
Answer:
a. h = 60t − 4.9t²
b. 12.2 seconds
c. 183.7 meters
Step-by-step explanation:
a. Given:
y₀ = 0 m
v₀ = 60 m/s
a = -9.8 m/s²
y = y₀ + v₀ t + ½ at²
h = 0 m + (60 m/s) t + ½ (-9.8 m/s²) t²
h = 60t − 4.9t²
b. When the ball lands, h = 0.
0 = 60t − 4.9t²
0 = t (60 − 4.9t)
t = 0 or 12.2
The ball lands after 12.2 seconds.
c. The maximum height is at the vertex of the parabola.
t = -b / (2a)
t = -60 / (2 × -4.9)
t = 6.1 seconds
Alternatively, the maximum height is reached at half the time it takes to land.
t = 12.2 / 2
t = 6.1 seconds
After 6.1 seconds, the height reached is:
h = 60 (6.1) − 4.9 (6.1)²
h = 183.7 meters
