All categories

2 years ago

Which of the following is equivalent to 3.39 x 10^8 ml?

Mathematics

1 answer:

Volgvan2 years ago

5 0

Answer:

Option E

Step-by-step explanation:

1 mL = 10^-1 cL

3.39 x 10^8 ml = 3.39 × 10⁷ cL

You might be interested in

1. SAT Math scores in recent years have had means around 490 and standard deviations

tatiyna

Answer:

´The variance is 10000

Step-by-step explanation:

The variance is defined as the square of standard deviation, consequently it is as follows:

σ^2= $100^{2}$

σ^2=10000

3 0

2 years ago

Someone please help me with this math question!

stepladder [879]

$1.25x + 2.5 \ \textless \ 2.75x - 6.5 \\ \\ 2.5 \ \textless \ 2.75x - 6.5 - 1.25x \ / \ subtract \ 1.25x \ both \ sides \\ \\ 2.5 \ \textless \ 1.5x - 6.5 \ / \ simplify \\ \\ 2.5 + 6.5 \ \textless \ 1.5x \ / \ add \ 6.5 \ both \ sides \\ \\ 9 \ \textless \ 1.5x \ / \ simplify \\ \\ 6 \ \textless \ x \ / \ divide \ both \ sides \ 1.5 \\ \\ x \ \textgreater \ 6 \ / \ change \ sides \\ \\ Answer: x \ \textgreater \ 6 (A)$

8 0

2 years ago

Read 2 more answers

Charmaine pumped 42 gallons of water out of her pool. This was done over a period of 7 minutes at a constant rate. What was the

Mariana [72]

The answer is 6 bc take 42 divided by 7 = 6

7 0

2 years ago

Read 2 more answers

How do I do probability?

Katen [24]

Probability is the measurement of the likelihood of something happening

So, looking through the different questions, whether they have a graph or picture, you look at the numbers and divide by the total to determine the probablility.

Hope this helps

3 0

3 years ago

Read 2 more answers

Explain how to find each root, with its multiplicity, for the polynomial y=x^5-27x^2.

Nuetrik [128]

The roots of $y = x^{5}-27\cdot x^{2}$ are 0 (multiplicity 2), -3 (multiplicity 1), $-\frac{3}{2}+i\,\frac{3\sqrt{3}}{2}$ (multiplicity 1) and $-\frac{3}{2}-i\,\frac{3\sqrt{3}}{2}$ (multiplicity 1).

The characteristics of the polynomial can be derived from algebraic techniques. Roots and multiplicity can be found by <em>factoring</em> the polynomial. The multiplicity is represented by a power binomial of the form:

$(x-r_{i})^{m},\,m \le n$ (1)

Where $n$ is the grade of the polynomial.

Now we proceed to factor the formula:

$y = x^{5}-27\cdot x^{2}$

$y = x^{2}\cdot (x^{3}-27)$

$y = x^{2}\cdot (x^{2}+3\cdot x +9)\cdot (x-3)$

Please notice that $x^{2}+3\cdot x + 9$ have two complex roots.

$y = x^{2}\cdot \left(x+\frac{3}{2}-i\,\frac{3\sqrt{3}}{2} \right)\cdot \left(x+\frac{3}{2}+i\,\frac{3\sqrt{3}}{3} \right)\cdot (x-3)$

The roots of $y = x^{5}-27\cdot x^{2}$ are 0 (multiplicity 2), -3 (multiplicity 1), $-\frac{3}{2}+i\,\frac{3\sqrt{3}}{2}$ (multiplicity 1) and $-\frac{3}{2}-i\,\frac{3\sqrt{3}}{2}$ (multiplicity 1).

We kindly invite to see this question on polynomials: brainly.com/question/1218505

7 0

2 years ago