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Grace [21]
3 years ago
10

What are the two solutions of 2x2 = –x2 – 5x – 1?

Mathematics
1 answer:
dybincka [34]3 years ago
8 0

Answer:

x=1+√334, x=1−√334

Step-by-step explanation:

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Find sin θ if θ is in Quadrant III and tan θ = . 0.958
Leokris [45]
Use the following identities:
sec^2 = 1  + tan^2 \\  \\ sec = \frac{1}{cos} \\  \\ sin^2 = 1 - cos^2
Also because the angle is in quadrant 3, sin must be negative.
Therefore
sin = - \sqrt{1 - \frac{1}{1 + tan^2}}
Subbing in tan = 0.958
sin \theta = -0.69178
7 0
3 years ago
I really need help with this question!
m_a_m_a [10]

Answer:

(s-6)/r

option D

Step-by-step explanation:

The slope-intercept form a line is y=mx+b where m is the slope and b is the y-intercept.

Compare y=mx+b and y=cx+6, we see that m=c and c is the slope.

Now we are also given that (r,s) is on our line which means s=c(r)+6.

We need to solve this for c to put c in terms of r and s as desired.

s=cr+6

Subtract 6 on both sides:

s-6=cr

Divide both sides by r:

(s-6)/r=c

The slope in terms of r and s is:

(s-6)/r.

6 0
4 years ago
Suppose a triangle has two sides of length 32 and 35, and that the angle
pantera1 [17]

Answer:

The third side is around 58.043

Step-by-step explanation:

Use the law of cosines:  c^2=a^2+b^2-2abcos(C)

Plug in the two sides we know (into a and b) and the angle we know (into angle C).

Thus:

c^2=32^2+35^2-2(32)(35)cos(120)

Use a calculator:

c^2=3369\\

c=58.043087...

(Note: Make sure you're in Degrees mode.)

3 0
3 years ago
HELP PLEASE EQUATION OF PARABOLA
Masteriza [31]

It has a minimum value at x = 3 and f(x) = 4

Vertex form is

f(x) = a(x - 3)^2 + 4 where a is some constant to be found

From the graph when x = 5 f(x) = 15, so

15 = a * 2^2 + 4

a = 15-4/4 = 11/4

so our equation is f(x) = 11/4(x - 3)^2 + 4

6 0
4 years ago
What is the (GCF) of the sum 44+40=??
svet-max [94.6K]
The sum of 44+40 is 84 then the greatest common factor would be 4 because when you divide 84 and 4 you get 21 (the GCF is 4)
8 0
3 years ago
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