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juin [17]
3 years ago
11

Suppose you have a dog-walking business after school for which you charge each customer $3 per hour plus an additional $10. What

equation could be written to show this relationship?
Mathematics
1 answer:
kherson [118]3 years ago
3 0
3x+10 is your answer
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Write 2.96 as a mixed number or fraction in simplest form show your work
Readme [11.4K]
<h3>Hey there </h3><h3>Improper Fraction: \frac{74}{25 }</h3><h3>Mixed number/ Fraction : 2\frac{24}{25}</h3><h3>Check to see if it gives your decimal </h3><h3>\frac{296/4}{100/4}</h3><h3>\frac{296}{4} → 74 </h3><h3>\frac{100}{4} →25</h3><h3>We now have: \frac{74}{25}</h3><h3>Therefore, your result (answer) is: 2\frac{24}{25}</h3><h3>Good luck on your assignment and enjoy your day!</h3><h3>~LoveYourselfFirst:)</h3>
3 0
3 years ago
Hi!
Elina [12.6K]

Answer:

404.09x cm³ (to 5 s.f.),

where x is the unknown height of the shape.

Step-by-step explanation:

Volume of the shape

= base area × height

= (large semicircle- small semicircle) × thickness of shape

Area of circle= \pi {r}^{2}

Area of semicircle= \frac{1}{2} (\pi)( {r}^{2} )

Diameter of small circle= 14

Radius= diameter ÷2

radius= 14 ÷2

radius = 7 cm

Area of small semicircle

=  \frac{1}{2} (\pi)( {7}^{2} ) \\  =  \frac{49}{2} \pi

Radius of large semicircle

= 35 ÷2

= 17.5 cm

Area of large semicircle

= \frac{1}{2} (\pi)( {17.5}^{2} ) \\  =  \frac{1225}{8} \pi

Base area of shape

= \frac{1225}{8}\pi  -  \frac{49}{2} \pi \\  =  \frac{1029}{8} \pi

Since the height if the shape is not given, I'm afraid I cant help you find the volume.

Let the height of the shape be x cm.

Volume of shape= \frac{1029x}{8} \pi \: cm^{3}

3 0
3 years ago
Aiden invested $43,000 in an account paying an interest rate of 9\tfrac{3}{4}9
Alex Ar [27]

Answer:

all your numbers are mixed up, can you fix your question?

5 0
3 years ago
PLZ HELP ASAP!!! NEED TO FINISH!!!! BRAINLIEST ANSWER IF CORRECT!
scZoUnD [109]

Answer:

about 10,652 balls

Step-by-step explanation:

The length of the court is 94 ft × 12 in/ft = 1128 in. That is 1128/8.5 ≈ 132.7 times the diameter of a ball.

The width of the court is 50 ft × 12 in/ft = 600 in. That is 600/8.5 ≈ 70.6 times the diameter of a ball.

When the balls are hexagonally packed, their row spacing is only (√3)/2 ≈ 0.866 times the ball diameter, so by cutting out one ball per row on alternate rows, about 15% more rows can be put in place. That is, there can be 81 rows of balls, alternating between 132 and 131 balls per row.

The number of balls that fit in that arrangement is ...

  132×81 - 40 = 10,652

___

Since there is some extra space beyond the last row, the balls can be "randomized" and a few more balls added, probably at least 2 or 3.

4 0
3 years ago
(02.05 MC)<br>Graph g(x), where f(x) = 3x - 1 and g(x) = f(x + 1).<br>​
RideAnS [48]

Answer:

<em>Graphs in the figure below</em>

Step-by-step explanation:

<u>Graphs</u>

We are given the functions:

f(x)=3x-1

g(x)=f(x+1)

The graph of f can be drawn by calculating some points. For x={-1,0,1,2}

We calculate y:

y=3*(-1)-1 = -4. Ordered pair: (-1,-4)

y=3*(0)-1 = -1. Ordered pair: (0,-1)

y=3*(1)-1 = 2. Ordered pair: (1,2)

y=3*(2)-1 = 5. Ordered pair: (2,5)

The graph of g is similar to the graph of f, but the x-coordinates are shifted left by one unit:

Ordered pair: (-2,-4)

Ordered pair: (-1,-1)

Ordered pair: (0,2)

Ordered pair: (1,5)

Both graphs are shown in the image provided

3 0
3 years ago
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