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juin [17]
2 years ago
11

Suppose you have a dog-walking business after school for which you charge each customer $3 per hour plus an additional $10. What

equation could be written to show this relationship?
Mathematics
1 answer:
kherson [118]2 years ago
3 0
3x+10 is your answer
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What is 56/15 as a decimal rounded to the nearest tenth
stepladder [879]

Answer:

3.73

Step-by-step explanation:

56/15

3 11/15

3.73

4 0
2 years ago
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20 points
Fantom [35]

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The value 4.5 is rational and the value 15−−√ is irrational. The sum of 4.5 and 15−−√ has a non-repeating and non-terminating decimal expansion. Therefore, the sum of 4.5 and 15−−√ is irrational. I can't explan but that's the correct Answer

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Over 6.8 months, a tree grew 7.48 inches.
evablogger [386]
The tree's grow rate is 1.1 per month
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3 years ago
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Solve the equation 0.3x-2=0.1(x+20) whats the solution set?
Inga [223]

x = 40/2 = 20 i think thsts the answer if I was wrong you have to right to slap my face

7 0
3 years ago
An engineer is designing a large steel pad to be installed on the deck of an aircraft carrier. Its total volume will be 18 yd^3.
Shtirlitz [24]

Answer:

The cost of the material for the full-sized pad is;

d) 222,750.00

Step-by-step explanation:

The parameters of the steel pad and the scale model are;

The volume of the deck = 18 yd³

The dimensions of the model of the same material = 6 feet by 4.5 feet and 4.5 inches thick

The weight of the sample, m₂ = 75 lbs

The cost of the steel, P = $55/lb

The dimensions of the sample in yards are;

6 feet = 2 yards, 4.5 feet = 1.5 yards, and 4 inches = 0.\overline 1 yards

The volume of the sample, V₂ = 2 yd. × 1.5 yd. × 0.\overline 1 yd. =  (1/3) yd.³

The density of the sample material, ρ = m₂/V₂

∴ The density of the sample material, ρ = 75 lbs/((1/3)yd.³) = 225 lbs/yd³

Therefore, the density of the material of the pad, ρ = 225 lbs/yd³

The mass of the steel  pad, m₁ = ρ × V₁

∴ The mass of the steel  pad, m₁ = 225 lbs/yd³ × 18 yd³ = 4,050 lbs

The cost of the material for the full-sized steel pad, C = m₁ × P

∴ C = 4,050 lbs × $55/lb = $222,750

6 0
3 years ago
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