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jarptica [38.1K]
3 years ago
12

How many ways can you arrange 8 objects?

Mathematics
2 answers:
eduard3 years ago
8 0

Answer:

8! = 40320

Step-by-step explanation:

there are 8 for first, then 7 for second and so on for 1 for the 8th  , so it's 8!

Sergio [31]3 years ago
7 0

Answer:

40,320

Step-by-step explanation:

The first object in the arrangement can be chosen 8 ways. The second, 7 ways (after the first one is chosen). And so on down to the last object, which will be the only remaining one. Altogether, the number of ways you can arrange the objects is ...

8·7·6·5·4·3·2·1 = 8! = 40,320

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garik1379 [7]
<span>2(30)+2x=860 

This is because the 4 sides of the rectangle add up to the perimeter. 
The unknown side is x, and there are two of those, and there are also two sides of 30. 
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So: 
2(30) + 2x = 860</span>
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<u>Explanation:</u>

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On differentiating the equation in terms of x

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On differentiating dy/dx we get,

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Therefore, the second derivative at the point (2,2) is 34/9

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