How many ways can you arrange 8 objects?

Mathematics

2 answers:

eduard4 years ago

8 0

Answer:

8! = 40320

Step-by-step explanation:

there are 8 for first, then 7 for second and so on for 1 for the 8th , so it's 8!

Sergio [31]4 years ago

7 0

Answer:

40,320

Step-by-step explanation:

The first object in the arrangement can be chosen 8 ways. The second, 7 ways (after the first one is chosen). And so on down to the last object, which will be the only remaining one. Altogether, the number of ways you can arrange the objects is ...

8·7·6·5·4·3·2·1 = 8! = 40,320

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Does anyone know this answer??

xxMikexx [17]

I believe by the first equation they are referring two a representation of the total amount of money made up by the two types of coins. I found this to be 0.05x + 0.10y = 3.50

In my work I solved for the amount of each coin- I assume this is what the final step of your problem entails. If you need any help understanding/ I misinterpreted something please feel free to comment and ask :)

#5c coins or x= 36

#10c coins or y= 17