Answer:
f(x)=x-2x+3; f(x)=-bx
x-2x=3=-bx
x+4x+3=0
(x+3) (x+1) = 0
x=-3 or x=-1
when x+-3. f(x)=b x(-3)=18
x=-1. f(x) = - b x (-1) = b
so system of equations : ( -3, -18)
; (-),b
Step-by-step explanation:
hope it helps
Answer:
sorry i dont know
Step-by-step explanation:
D=event that chip selected is defective
d=event that chip selected is NOT defective
Four possible scenarios for the first two selections:
P(DDD)=15/100*14/99*13/98=13/4620
P(DdD)=15/100*85/99*14/98=17/924
P(dDD)=85/100*15/99*14/99=17/924
P(ddD)=85/100*84/99*15/98=17/154
Probability of third selection being defective is the sum of all cases,
P(XXD)=P(DDD)+P(DdD)+P(dDD)+P(ddD)
=3/20
Answer:
Step-by-step explanation:
Find the are by multiplying all of the sides together, and you wil get your answer.