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Lana71 [14]
3 years ago
9

What is the relationship between 0.04 and 0.004?

Mathematics
2 answers:
Sonbull [250]3 years ago
6 0
0.04 is 10x greater than 0.004

hope this helps
Dahasolnce [82]3 years ago
5 0
I believe 0.04 is 10x larger than 0.004. I know this because 0.04^-10 = 0.004.

Hope this helped!
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I NEED THESE DONE OR I WONT GET A GOOD GRADE!!!!!
djverab [1.8K]

Answer:

14.x=-2

21. x=-2

23. x=5

7.x=12

2.x=49

Step-by-step explanation:

I got your back bro:

14. Subtract 7 on both sides. Then divide -16 by 8.      x=-2

21. Add 1 on both sides. Divide 18 by -9. x=-2

23. Subtract 24 on both sides, then divide -25 by -5. your answer is x=5.

7. Add 2/5 on both sides. then multiply 2 2/5 by the reciprocal of -1/5. Your answer is x=12

2. Subtract 5 on both sides. Multiply 14 by the reciprocal of 2/7, or 7/2. Your answer is 49.

Good luck!


3 0
3 years ago
I'm doing a stick and poke what should I do you can add a picture if you want (I'm not going to do something big just something
Alchen [17]
Ooh what about a skull w/ some flowers growing out of it?
7 0
2 years ago
Read 2 more answers
What is the formula for the following arithmetic sequence? 12, 6, 0, -6, ...
bixtya [17]

Answer:

an= 12 + (-6)(n-1)

Step-by-step explanation:

you should find two values: a1 and d

a1= first number =12

d= a number of the sequence mines the number of the sequence before the one you chose = 0-6 = -6

a1+(n-1)d= 12-6(n-1)

6 0
3 years ago
Read 2 more answers
????????????????????
xenn [34]

Answer:

ASA

Step-by-step explanation:

In the 2 triangles

∠J = ∠L

side OJ = side IL

∠O = ∠I

The triangles are congruent by the angle/side/angle (ASA ) postulate

5 0
3 years ago
Which shows one way to determine the factors of x3 – 9x2 + 5x – 45 by grouping?
Valentin [98]
Factoring by grouping usually pairs up the first 2 sets of expressions with the second 2 sets.  Ours looks like this, then:  (x^3-9x^2)+(5x-45)=0.  If we factor out the common x-squared in the first set of parenthesis, along with factoring out the common 5 in the second set, we get this:  x^2(x-9)+5(x-9).  Now the common expression that can be factored out is the (x-9).  When we do that, here's what it looks like:  (x-9)(x^2+5).  I'm not sure how far you are going with this.  You could set each of those equal to 0 and solve for x in each case.  The first one is easy.  If x - 9 = 0, then x = 9.  The second one involves the imaginary i since x^2 = -5.  In that case,  x=i \sqrt{5},-i \sqrt{5}.  Hopefully, in what I have given you, you can find what you're looking for.
7 0
3 years ago
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