Answer:
x = 2 cm
y = 2 cm
A(max) = 4 cm²
Step-by-step explanation: See Annex
The right isosceles triangle has two 45° angles and the right angle.
tan 45° = 1 = x / 4 - y or x = 4 - y y = 4 - x
A(r) = x* y
Area of the rectangle as a function of x
A(x) = x * ( 4 - x ) A(x) = 4*x - x²
Tacking derivatives on both sides of the equation:
A´(x) = 4 - 2*x A´(x) = 0 4 - 2*x = 0
2*x = 4
x = 2 cm
And y = 4 - 2 = 2 cm
The rectangle of maximum area result to be a square of side 2 cm
A(max) = 2*2 = 4 cm²
To find out if A(x) has a maximum in the point x = 2
We get the second derivative
A´´(x) = -2 A´´(x) < 0 then A(x) has a maximum at x = 2
Arc length, (s)=(radius, r)(central angle, q)
s=rq
q=s/r
q=4/10
q=2/5, or 0.4 radians
Answer:
3.85 % to 2 decimal places
Step-by-step explanation:
If you have Rs5 profit it means that you have sold it for 135
Do 5 / 130
Then times the answer by 100 *100
Answer:
1/9
Step-by-step explanation:
(-3)^0 = 1
(-3)^2 = 9
so, 1/9