The answer is 4000 because the value of 4 is 40000 so times that by 1/10 gives you 4000
Answer: 22.5 . The weight of the elephant is "22.5 times greater" than the weight of the lion.
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Explanation:
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(weight of lion) * (x) = (eight of the elephant) ; Solve for "x" .
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→ Divide each side of the equation by "(weight of lion)" ;
to isolate "x" on one side of the equation ; and to solve for "x" ;
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→ (weight of lion)*(x) / (weight of lion) = (weight of the elephant) /
(weight of lion) ;
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→ x = (weight of the elephant) / (weight of lion) ;
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→ Plug in our "given values" ; and solve for "x" ;
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→ x = (<span>9*10</span>³) / (4*10²) = (9*10⁽³⁻²⁾) / 4 = (9*10¹) / 4 ;
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→ x = 90 /4 = 25/2 = 22.5 ; which is our answer.
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Step-by-step explanation:
3/4:2/5=3/4×5/2=15/8
3/8 ÷ 2/12=3/8 ×12/2=36/16=9/4
First, distribute the 12
156-168-15=16+4+x
-27=20+x
-47=x
Answer:
(1) The correct option is (A).
(2) The probability that Aadi will get Tails is 
.
Step-by-step explanation:
It is provided that:
- Eric throws a biased coin 10 times. He gets 3 tails.
- Sue throw the same coin 50 times. She gets 20 tails.
The probability of tail in both cases is:
(1)
According to the Central limit theorem, if from an unknown population large samples of sizes n > 30, are selected and the sample proportion for each sample is computed then the sampling distribution of sample proportion follows a Normal distribution.
In this case we need to compute the proportion of tails.
Then according to the Central limit theorem, Sue's estimate is best because she throws it <em>n = </em>50 > 30 times.
Thus, the correct option is (A).
(2)
As explained in the first part that Sue's estimate is best for getting a tail, the probability that Aadi will get Tails when he tosses the coin once is:
Thus, the probability that Aadi will get Tails is .
