Here, the union tells us that at least one of the original inequalities must be true. We solve each separately, first.
x + 2 < 5 OR x - 7 > -6
x < 3 OR x - 7 > -6 subtract 2 on both sides of the equation left of the OR
x < 3 OR x > 1 add 7 on both sides of the equation right of the OR
Thus x < 3 or x > 1. In set notation, {x | x < 3 or x > 1} is true.
Answer:
83% are boys
Step-by-step explanation:
Im not sure if you have to round but you take the total number of family members (6) and divide it by how many boys (5) which would be 0.8333333 which you can round to either 80 or 83
2y - 8 = 6x
2(3x + 2) - 8 = 6x
6x + 4 - 8 = 6x
6x - 4 = 6x
-4 = 0
this system has no solutions