Answer:
The answer is C. the energy transferred between objects at different temperatures.
Explanation:
I did some research, I hope this helps.
To solve this problem, we begin by first calculating the area of the front lawn. The length and width of the lawn was given and the area of a rectangle is given by the formula: Area = length x width. Thus, the area of the front lawn can be obtained by multiplying 18 ft by 20 ft, wherein we get 360 ft^2 as the area.
Second, the problem indicated that each square foot of lawn accumulates 1450 new snow flakes per minute. This can be translated into the expression 1450 snow flakes/ (minute·ft^2). In this way, we can convert it to units of mass (kg). Afterwards, we simply need to multiply it to the area of the lawn and convert minute to hour. The following expression is then used:
1450 snow flakes/ (minute·ft^2) x 1.90 mg/snow flake x 1 g/1000 mg x 1kg/1000 g x 360 ft^2 x 60 minutes/hour = 59.508 kg snow flake/hour
It is then calculated that 59.508 kg of snow flake accumulates in the lawn every hour.
Answer:
1. The physical states of the reactants and products.
2. The concentration of the reactants and products.
3. The conditions such as temperature, pressure or catalyst etc which affect the reaction.
4. The heat changes accompanying the reaction i.e. whether heat is evolved or absorbed during the reaction.
Explanation:
Hope it helps! ^w^
Crystal system
Hardness
Tenacity or Toughness