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3 years ago

How do densities of the solids compare to those of the liquid?

1 answer:

3 0

Generally, solids are denser than liquid, which is denser than gas of one particular substance. In liquid phase, molecules are freer and can move around, so it is less dense than solid, but denser than gas, in which the molecules move at high speed with large separation from one another.

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A thermally isolated system is made up of a hot piece of aluminum and a cold piece of copper; the aluminum and the copper are in

Illusion [34]

Answer:

Copper is the object that experiences the greater temperature change.

Explanation:

Thermally isolated system means that the system does not exchange thermal energy with the surroundings.

Hence, any thermal exchange, in virtue of the temperature difference of the aluminum and copper pieces, is between them.

In consequence, the law of conservation of energy states that the heat lost by the hot substance will be gained by the cold matter.

In equations, that is:

Heat lost by aluminum = heat gained by copper.

Now, the gain or loss or heat of a substance, Q, is related with the mass (m), the specific heat (Cs), and the cahnge of temperature (ΔT), per the equation:

Q = m × Cs × ΔT

∴ Q lost by aluminum = Q gained copper ⇒

[m × Cs × ΔT ] aluminum = [m × Cs × ΔT ] copper.

Under the reasoning assumption that the masses of aluminum and copper are equal, the equations is simplified to:

[Cs × ΔT ] aluminum = [Cs × ΔT ] copper.

Cs aluminum / Cs copper = ΔT copper / ΔT aluminum

Cs aluminum > 2 × Cs copper ⇒ Cs

Cs aluminum / Cs copper > 2 ΔT copper / ΔT aluminum

ΔT copper / ΔT aluminum > 2

ΔT copper > 2 × ΔT aluminum

In words, since it is stated that the specific heat of aluminum is more than double that of copper, in order to keep the equality, ΔT of copper shall be more than double ΔT of aluminum.

Hence, the conclusion is that the object that experiences the greater temperature change is copper (the one with the lower specific heat), under the assumption that both objects have the same amount of matter (mass).

6 0

3 years ago

Include a map with points where neon can be found.

nalin [4]

Here is some information: "Neon is a chemical element with symbol Ne and atomic number 10. It is in group 18 of the periodic table. Neon is a colorless, odorless, inert monatomic gas under standard conditions, with about two-thirds the density of air. It was discovered in 1898 as one of the three residual rare inert elements remaining in dry air, after nitrogen, oxygen, argon and carbon dioxide were removed. Neon was the second of these three rare gases to be discovered, and was immediately recognized as a new element from its bright red emission spectrum. The name neon is derived from the Greek word, νέον, neuter singular form of νέος, meaning new. Neon is chemically inert and forms no uncharged chemical compounds. The compounds of neon include ionic molecules, molecules held together by van der Waals forces and clathrates."

Also: "Neon is rare on Earth, found in the Earth's atmosphere at 1 part in 55,000, or 18.2 ppm by volume (this is about the same as the molecule or mole fraction), or 1 part in 79,000 of air by mass."

Also I only found one if that is okay but here it is: It is the place where it is a city and most people find most neon there.

5 0

3 years ago

Which of the following shows the valency of 1?

Oliga [24]

$\huge \bf༆ Answer ༄$

The element having valency of 1 is ~

Sodium (Na)

6 0

2 years ago

Read 2 more answers

You wish to add 5 mg/l naocl as cl2 to a solution in a disinfection test, and you have a stock solution (household bleach) that

Alecsey [184]

Answer: -

0.1 ml of bleach should be added to each liter of test solution.

Explanation:-

Let the volume of bleach to be added is B ml.

Density of stock solution = 1.0 g/ml

Mass of stock solution = Volume of stock x density of stock

= B ml x 1.0 g/ml

= B g

Amount of NaOCl in this stock solution = 5% of B g

= $\frac{5}{100}$ x B g

= 0.05 B g

Now each test solution must be added 5 mg/l NaOCl.

Thus each liter of test solution must have 5 mg.

Thus 0.05 B g = 5 mg

= 0.005 g

B = $\frac{0.005}{0.05}$

= 0.1

Thus 0.1 ml of bleach should be added to each liter of test solution.

4 0

3 years ago

People who work with radioactive materials often wear a _________ to reveal how much radiation they have been exposed to. A. fil

nekit [7.7K]

People who work with radioactive materials often wear a film badge to reveal how much radiation they have been exposed to. The film badge dosimeter or the film badge is a dosimeter worn by these people working with materials that are radioactive for the purpose of monitoring cumulative radiation dose due to ionizing radiation. The badge has two parts; the photographic film, and a holder.

3 0

3 years ago

Read 2 more answers