Energy is required to change the phase of a substance, such as the energy to break the bonds between molecules in a block of ice so it may melt.
During a phase change energy my be added or subtracted from a system, but the temperature will not change. The temperature will change only when the phase change has completed. No temperature change occurs from heat transfer if ice melts and becomes liquid water (i.e., during a phase change). For example, consider water dripping from icicles melting on a roof warmed by the Sun. Conversely, water freezes in an ice tray cooled by lower-temperature surroundings. Energy is required to melt a solid because the cohesive bonds between the molecules in the solid must be broken apart so that the molecules can move around at comparable kinetic energies; thus, there is no rise in temperature.
Explanation:
Bernoulli equation for the flow between bottom of the tank and pipe exit point is as follows.
= 
![\frac{(100 \times 144)}{62.43} + 0 + h[tex] = [tex]\frac{(50 \times 144)}{(62.43)} + \frac{(70)^{2}}{2(32.2)} + 0 + 40 + 60](https://tex.z-dn.net/?f=%5Cfrac%7B%28100%20%5Ctimes%20144%29%7D%7B62.43%7D%20%2B%200%20%2B%20h%5Btex%5D%20%3D%20%5Btex%5D%5Cfrac%7B%2850%20%5Ctimes%20144%29%7D%7B%2862.43%29%7D%20%2B%20%5Cfrac%7B%2870%29%5E%7B2%7D%7D%7B2%2832.2%29%7D%20%2B%200%20%2B%2040%20%2B%2060)
h = 
= 60.76 ft
Hence, formula to calculate theoretical power produced by the turbine is as follows.
P = mgh
= 
= 6076 lb.ft/s
= 11.047 hp
Efficiency of the turbine will be as follows.
=
× 100%
=
= 52.684%
Thus, we can conclude that the efficiency of the turbine is 52.684%.
Answer:
Aluminum lodide - 680 degrees
fructose- 824 degrees
potassium bromide- 2,615 degrees
calcium bromide 3, 515 degrees
lowest boiling point is 680 and highest is 3,515.
hope this helps:)
2.15 x 10⁻³mL
Explanation:
Given parameter:
Volume of blood sample in uL = 2.15uL
Conversion uL → mL
micro- and milli- are both prefixes of sub-units.
liter is a unit of volume of a substance.
micro - is 10⁻⁶
milli- is of the order 10⁻³
The problem is converting from micro to milli:
if we multiply 10⁻⁶ by 10³ we would have our milli;
1000uL = 1mL
2.15uL : 2.15uL x
= 2.15 x 10⁻³mL
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