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Luda [366]
2 years ago
13

Which diagram best illustrates the stage in the formation of the solar system at which the sun formed?​

Chemistry
1 answer:
iogann1982 [59]2 years ago
4 0

Answer:

A

Explanation:

Every thing was first a bunch of gas.

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If you use a horizontal force of 32.0 N to slide a 12.5 kg wooden crate across a floor at a constant velocity, what is the coeff
sergejj [24]

Answer:

Value of coefficient of kinetic friction is 0.26 .

Explanation:

Given:

Mass of wooden crate, m = 12.5 kg.

Horizontal force to keep the block moving with constant velocity, F = 32.0 N.

Since, the block is moving with constant velocity.

So, net force experience by it is zero.

Therefore, fore of friction is equal to applied force.

Now, force of friction , F=\mu_kN  (  here \mu_k is coefficient of kinetic friction and N is normal force)

Therefore, \mu_kN=\mu_k\times mg=\mu_k\times 12.5 \times 9.8=122.5\times \mu_k

Now, both forces are equal.

122.5\times \mu_k=32\\\mu_k=\dfrac{32}{122.5}=0.26      

The value of coefficient of kinetic friction is 0.26 .

Hence, it is the required solution.

6 0
3 years ago
Which celestial object is found in kuiper belt
romanna [79]

The Kuiper belt is home to three officially recognized dwarf planets: Pluto, Haumea, and Makemake. Some of the Solar System's moons, such as Neptune's Triton and Saturn's Phoebe, are also thought to have originated in the region.

4 0
3 years ago
does the nitro group on the pyridine ring make the ring more electron rich or more electron deficient
Arte-miy333 [17]

Answer:

more electron deficient

Explanation:

The nitro group is an electron withdrawing group. It withdraws electrons from the pyridine ring by resonance.

This electron withdrawal by resonance makes the pyridine ring less electron rich or more electron deficient.

Hence, the nitro group makes the pyrinde ring more electron deficient

3 0
2 years ago
Help me, it’s pretty easy science moon stuff !
trasher [3.6K]
Hello :)
Based on the information I received reading the picture, the answer should be “B”

Explanation: if I am wrong I’m very sorry. But that should be the answer
8 0
2 years ago
Read 2 more answers
Acetylene, c2h2, has a standard enthalpy of formation, δh° = 226.7 kj/mol, and a standard entropy change for its formation from
VLD [36.1K]
ΔG⁰ = ΔH⁰ - T ΔS⁰

ΔG⁰ : Standard free energy of formation of acetylene

ΔH⁰ : Standard enthalpy of formation (226.7 kJ/mol)

ΔS⁰ : Standard entropy change (58.8 J / K. mol)

T : Temperature 25°C = 298 K (room temperature)

ΔG⁰ = 226.7 - (298 x 58.8 x 10⁻³) = 209.2 kJ /mol
5 0
2 years ago
Read 2 more answers
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