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wel
3 years ago
12

An atomic scientist was studying an atom and through experimentation found that the total negative charge of the area surroundin

g the nucleus is -9. Which statement correctly describes this atom?
This atom has nine clouds.
This atom has nine electrons.
This atom has nine neutrons.
This atom has nine protons.
Chemistry
1 answer:
Studentka2010 [4]3 years ago
5 0

Answer:

This atom has nine electrons

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5. Geologists think that the inner and outer cores of Earth consist of<br> iron and nickel.
wolverine [178]

Answer:

is this true/false? if so its true.

Explanation:

3 0
3 years ago
A homogenerous mixture is a mixture where you can see the different parts.<br> True<br> or<br> False
ollegr [7]

Answer:

the nwser is false

Explanation:

Its false becuase Homomogeneous means "One" and if you can see different parts of it then its not homogeneous. hope this helps!

3 0
3 years ago
PLEASE HELP!!!
lukranit [14]

Answer:

b

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6 0
3 years ago
Determine el número de moles presentes en una esfera de titaniode 0.5 cm de radio, sabiendo que la densidad del titanio es de 45
ludmilkaskok [199]

Answer:

0.0493 moles de Titanio

Explanation:

Primero, debemos hallar el volumen de la esfera. Usando la densidad podemos hallar la masa de titanio y usando la masa atómica encontraremos las moles de titanio:

<em>Volumen de la esfera:</em>

<em>Volumen esfera  = 4/3π * Radio³</em>

Volumen = 0.5236cm³

En m³ (1m³ = 1x10⁶cm³):

0.5236cm³ * (1m³ / 1x10⁶cm³) = 5.36x10⁻⁷m³

<em>Masa en gramos:</em>

5.36x10⁻⁷m³ * (4507kg / m³) = 2.36x10⁻³kg * (1000g / 1kg) = 2.36g de Titanio

<em>Moles -Masa molar Ti: 47.867g/mol-:</em>

2.36g de Titanio * (1mol / 47.867g) =

<h3>0.0493 moles de Titanio</h3>
4 0
3 years ago
A student pipets 10 ml of a 0.0693 m solution of kbr into a 500 ml volumetric flask and dilutes to the mark. what is the concent
Sonja [21]

The initial concentration of solution is 0.0693 M. The volume of solution taken is 10 mL and it is diluted to a final volume of 500 mL.

According to dilution law, the product of initial concentration and volume is equal to the product of final concentration and volume as follows:

C_{1}V_{1}=C_{2}V_{2}

Here, C_{1} is initial concentration, C_{2} is final concentration, V_{1} is initial volume and V_{2} is final volume.

Rearranging to calculate final concentration,

C_{2}=\frac{C_{1}\times V_{1}}{V_{2}}

Putting the values,

C_{2}=\frac{0.0693 M\times 10 mL}{500 mL}=0.001386 M

Therefore, concentration of the resulting solution is 0.001386 M.

7 0
3 years ago
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