I would have to say the answer is a. True.
Answer is: increase the concentration of NiCO₄ and <span>withdraw CO from the products as it is forming.
Balanced chemical reaction: NiCO</span>₄(g) ⇄ Ni(s) + 4CO(g).
According to Le Chatelier's Principle the position of equilibrium
moves to counteract the change:
1) the position of equilibrium will move to the right, so
that the concentration of nickel carbonyl gas decreases again and produce more nickel.
2) the position of equilibrium will move to the right, if we decrease concentration of carbon monoxide, more nickel carbonyl gas will decompose and produce more nickel.
The question is incomplete, complete question is :
In an organic structure, you can classify each of the carbons as follows: Primary carbon (1°) = carbon bonded to just 1 other carbon group Secondary carbon (2°) = carbon bonded to 2 other carbon groups Tertiary carbon (3°) = carbon bonded to 3 other carbon groups Quaternary carbon (4°) = carbon bonded to 4 other carbon groups How many carbons of each classification are in the structure below? How many total carbons are in the structure? How many primary carbons are in the structure? How many secondary carbons are in the structure? How many tertiary carbons are in the structure? How many quaternary carbons are in the structure?
Structure is given in an image?
Answer:
There are 10 carbon atoms in the given structures out of which 6 are 1° , 1 is 2° , 2 are 3° and 1 is 4°.
Explanation:
Total numbers of carbon = 10
Number of primary carbons that is carbon joined to just single carbon atom = 6
Number of secondary carbons that is carbon joined to two carbon atoms = 1
Number of tertiary carbons that is carbon joined to three carbon atoms = 2
Number of quartenary carbons that is carbon joined to four carbon atoms = 1
So, there are 10 carbon atoms in the given structures out of which 6 are 1° , 1 is 2° , 2 are 3° and 1 is 4°.