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kirza4 [7]
3 years ago
6

A) A cat dish has a mass of 1975 g and a volume of 7500ml. What is the overall density of the cat dish? B) find the maximum mass

that the cat dish can hold before it sinks
Chemistry
1 answer:
maxonik [38]3 years ago
5 0
What's the answer? It asked to be 20 characters long so just writing this.
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In the reaction C5H8+____ O2= 8H2O+5CO2
Romashka-Z-Leto [24]
I don't think that the whole question is posted here, but if you are looking for a way to balance this equation, I may have the answer. I believe the balanced equation is C5H8+9O2=4H2O+5CO2. If you need the reaction type, the answer is combustion. Hope this helps you.
7 0
3 years ago
PLS HELP ME WITH THIS ILL GIVE BRAINLIEST
anyanavicka [17]

Answer:

1 qualiative physical  

2 qualiative   chemical

3 quantitative physcial

4 quantiative chemical

5qualiative   physcial

6quatiative    chemcial

7quanatiative physcial

8 qualiative   chemical

9quatliate  physcial

6 0
2 years ago
What is the concentration of bromide, in ppm, if 12.41 g MgBr2 is dissolved in 2.55 L water.
pav-90 [236]

Answer:

concentration of bromide (Br⁻) = 4234 mg/L = 4234 ppm

Explanation:

ppm (parts per million) concentration is defined as the mass (in milligrams) of a substance dissolved in one liter of solution.

In our case we have:

mass of MgBr₂ = 12.41 g

volume of water (which is equal to the final solution volume) = 2.55 L

Now we devise the following reasoning:

if         12.41 g of MgBr₂ are dissolved in 2.55 L of water

then         X g of MgBr₂ are dissolved in 1 L of water

X = (1 × 12.41) / 2.55 = 4.867 g of MgBr₂

if in         184 g (1 mole) of MgBr₂ we have 160 g of Br⁻

then in   4.867 g of MgBr₂ we have Y g of Br⁻

Y = (4.867 × 160) / 184 = 4.232 g of bromide (Br⁻)

4.232 g of bromide (Br⁻) = 4234 mg of bromide (Br⁻)

concentration of bromide (Br⁻) = 4234 mg/L = 4234 ppm

7 0
3 years ago
How many valence electrons do the alkaline earth metals have?
fenix001 [56]

Answer:

\boxed{2}

Explanation:

Alkaline earth metals are in group 2. The number of valence electrons of elements in group 2 is 2.

5 0
3 years ago
Read 2 more answers
f the Ksp for HgBr2 is 2.8×10−14, and the mercury ion concentration in solution is 0.085 M, what does the bromide concentration
goldfiish [28.3K]

Answer:

0.057 M

Explanation:

Step 1: Given data

Solubility product constant (Ksp) for HgBr₂: 2.8 × 10⁻⁴

Concentration of mercury (II) ion: 0.085 M

Step 2: Write the reaction for the solution of HgBr₂

HgBr₂(s) ⇄ Hg²⁺(aq) + 2 Br⁻

Step 3: Calculate the bromide concentration needed for a precipitate to occur

The Ksp is:

Ksp = 2.8 × 10⁻⁴ = [Hg²⁺] × [Br⁻]²

[Br⁻] = √(2.8 × 10⁻⁴/0.085) = 0.057 M

7 0
3 years ago
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