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Burka [1]
3 years ago
12

Help! And plz do explain...

Mathematics
1 answer:
Nat2105 [25]3 years ago
6 0
1 mile is 5280 feet, therefore, we have 60 miles, and each mile is 5280 feet, so we multiply 5280 and 60, you get the answer of 316,800 feet.
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In the diagram which angle is part of a linear pair and part of a vertical pair
yulyashka [42]

Answer:

d. < EFA

Step-by-step explanation:

6 0
3 years ago
Mrs. Boggs writes the equation on the board.
Zigmanuir [339]

Answer:

(A).

Step-by-step explanation:

-8+3= -5      -8-(-3)= -5

           -5= -5

Hope this helps.

Please mark me as Brainliest. Thank You.

3 0
3 years ago
At a local university, a sample of 49 evening students was selected in order to determine whether the average age of the evening
pav-90 [236]

Answer:

z=\frac{23-21}{\frac{3.5}{\sqrt{49}}}=4    

p_v =2*P(z>4)=0.0000633  

When we compare the significance level \alpha=0.1 we see that p_v so we can reject the null hypothesis at 10% of significance. So the  the true mean is difference from 21 at this significance level.

Step-by-step explanation:

Data given and notation  

\bar X=23 represent the sample mean

\sigma=3.5 represent the population standard deviation

n=49 sample size  

\mu_o =21 represent the value that we want to test

\alpha=0.1 represent the significance level for the hypothesis test.  

z would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the average age of the evening students is significantly different from 21, the system of hypothesis would be:  

Null hypothesis:\mu = 21  

Alternative hypothesis:\mu \neq 21  

The statistic is given by:

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}  (1)  

Calculate the statistic

We can replace in formula (1) the info given like this:  

z=\frac{23-21}{\frac{3.5}{\sqrt{49}}}=4    

P-value

Since is a two sided test the p value would be:  

p_v =2*P(z>4)=0.0000633  

Conclusion  

When we compare the significance level \alpha=0.1 we see that p_v so we can reject the null hypothesis at 10% of significance. So the  the true mean is difference from 21 at this significance level.

8 0
3 years ago
The average birth weight of elephants is 200 pounds. Assume that the distribution of birth weights is Normal with a standard dev
zhenek [66]

The birth weight of elephants at the 85th percentile is 262.16 pounds

<h3>What is the standard deviation?</h3>

Standard deviation is defined as the amount of variation or the deviation of the numbers from each other.

Given that:-

The average birth weight of elephants is 200 pounds    \mu = 200

The deviation of 60 pounds.                                              \sigma = 60

The birth weight of elephants at the 85th percentile.      z = 85%= 1.036

Now from the formula of z-score:-

z=\dfrac{x-\mu}{\sigma}\\\\\\z=\dfrac{x-200}{60}\\\\\\1.036\times 60=x-200\\\\\\x=\ \ 262.16\ pounds

Hence the birth weight of elephants at the 85th percentile is 262.16 pounds

To know more about standard deviation follow

brainly.com/question/475676

#SPJ1

5 0
2 years ago
Can someone help me on finding the measure of each angle please? I'm struggling alot on this! :(
olga_2 [115]

Answer:

Step-by-step explanation:

The protractor has inner and outer readings. The inner reading has graduations with intervals of 10 degrees and the outer reading also has graduations with intervals of 10 degree. We will use the outer graduations to take readings. On the outer reading, the shortest graduations is in intervals of 1 degree while the shorter graduation is in intervals of 5 degrees. Therefore,

a) angle AFB is 55 degrees

b) angle BFE is 180 - 55 = 125 degrees.

c) angle DFA is 126 degrees

d) angle BFD is 60 + 5 + 6 = 71 degrees.

e) angle CFD is 36 degrees

8 0
3 years ago
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