Find the area of this question
1 answer:
You might be interested in
Answer:
The 95% confidence interval for the fraction of all shoppers during the year whose visit was because of a coupon they'd received in the mail is (0.2016, 0.2694).
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of , and a confidence level of
, we have the following confidence interval of proportions.
In which
z is the z-score that has a p-value of .
A store randomly samples 603 shoppers over the course of a year and finds that 142 of them made their visit because of a coupon they'd received in the mail.
This means that
95% confidence level
So , z is the value of Z that has a p-value of
, so
.
The lower limit of this interval is:
The upper limit of this interval is:
The 95% confidence interval for the fraction of all shoppers during the year whose visit was because of a coupon they'd received in the mail is (0.2016, 0.2694).
F you just want to see the really short way, just skip down to AAAAAAAAAAAA
so, here is the long explanation
exponential properties
don't forget pemdas
2x^2=2(x^2)
so
=
AAAAAAAAAAAAAAAAAAAAAAAA
so we see
the original equatio is
remember
so we can seperate the constants
we know that the placeholders cannot affet the position of the constants unless they are grouped together which they are not
terfor the answer must have 2/3 in it
the only one that hsa that is A
ANSWER IS A
so, here is the long explanation
exponential properties
don't forget pemdas
2x^2=2(x^2)
so
AAAAAAAAAAAAAAAAAAAAAAAA
so we see
the original equatio is
remember
so we can seperate the constants
we know that the placeholders cannot affet the position of the constants unless they are grouped together which they are not
terfor the answer must have 2/3 in it
the only one that hsa that is A
ANSWER IS A